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Anuta_ua [19.1K]
3 years ago
14

Which is a recursive formula for the sequence 99.4, 0, –99.4, –198.8, where f(1) = 99.4?

Mathematics
2 answers:
olga nikolaevna [1]3 years ago
7 0
F(n<span> + 1) = </span>f(n<span>) – 99.4, </span>n<span> ≥ 1</span>
aivan3 [116]3 years ago
4 0

Answer:

f(n+1)=f(n)-99.4

Step-by-step explanation:

We are given a sequence as:

 99.4,0,-99.4,-198.8, and so on

We can see that the sequence is constantly getting decreased by -99.4

i.e. f(1)=99.4

Then, f(2)=f(1)-99.4

              =99.4-99.4

             =0

f(3)=f(2)-99.4

   =0-99.4

   =-99.4

Hence, the recursive formula is:

 f(n+1)=f(n)-99.4

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