F(x)-- x2- 9x + 20/ X-5
2 answers:
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Answer:
Height = 5
Minimum number of vertices in a binary tree
whose height is h.
So, there must be At least one node at each of first h levels.
Minimum number of vertices = h
So, Minimum number of vertices of height 5 is 5
The maximum number of nodes in a binary tree of height h =
Substitute h = 5
The maximum number of nodes in a binary tree of height 5 =
The maximum number of nodes in a binary tree of height 5 = 63
So, the maximum number of vertices in a binary tree with height 5 is 63
Answer:
14.3 feet
Step-by-step explanation:
Let the height of the tree = x feet.
It is given that the horizontal distance from the base of tree = 10 feet and the angle of elevation to the nest is 55°.
So, we get the following figure.
As, we are obtaining a right angled triangle.
Using the trigonometric form for the angles of a right angled triangle, we get,
i.e.
i.e.
i.e.
i.e.
Hence, the height of the tree is 14.3 feet.
