3x/8-1=5/8<br> How do I start to find out the answer to this equation?

Find dy/dx by implicit differentiation for ysin(y) = xcos(x)

tatyana61 [14]

Answer:

$\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}$

Step-by-step explanation:

So we have:

$y\sin(y)=x\cos(x)$

And we want to find dy/dx.

So, let's take the derivative of both sides with respect to x:

$\frac{d}{dx}[y\sin(y)]=\frac{d}{dx}[x\cos(x)]$

Let's do each side individually.

Left Side:

We have:

$\frac{d}{dx}[y\sin(y)]$

We can use the product rule:

$(uv)'=u'v+uv'$

So, our derivative is:

$=\frac{d}{dx}[y]\sin(y)+y\frac{d}{dx}[\sin(y)]$

We must implicitly differentiate for y. This gives us:

$=\frac{dy}{dx}\sin(y)+y\frac{d}{dx}[\sin(y)]$

For the sin(y), we need to use the chain rule:

$u(v(x))'=u'(v(x))\cdot v'(x)$

Our u(x) is sin(x) and our v(x) is y. So, u'(x) is cos(x) and v'(x) is dy/dx.

So, our derivative is:

$=\frac{dy}{dx}\sin(y)+y(\cos(y)\cdot\frac{dy}{dx}})$

Simplify:

$=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}$

And we are done for the right.

Right Side:

We have:

$\frac{d}{dx}[x\cos(x)]$

This will be significantly easier since it's just x like normal.

Again, let's use the product rule:

$=\frac{d}{dx}[x]\cos(x)+x\frac{d}{dx}[\cos(x)]$

Differentiate:

$=\cos(x)-x\sin(x)$

So, our entire equation is:

$=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}=\cos(x)-x\sin(x)$

To find our derivative, we need to solve for dy/dx. So, let's factor out a dy/dx from the left. This yields:

$\frac{dy}{dx}(\sin(y)+y\cos(y))=\cos(x)-x\sin(x)$

Finally, divide everything by the expression inside the parentheses to obtain our derivative:

$\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}$

And we're done!

5 0

3 years ago

(7, 1) and (x, 4); m = 3/4<br> missing value<br> 50 POINTS

Sever21 [200]

Answer:

x = 11

Step-by-step explanation:

4 - 1 / x - 7 (simplify)

3 / x - 7 = 3/4 (multiply by x - 7)

3 = 3/4 (x - 7)

3 = 3/4x - 5.25 (add 5.25 to both sides)

8.25 = 3/4x (divide both sides by 8.25)

x = 11

sub into the formula to check:

4-1 / 11 - 7

3 / 4

7 0

3 years ago

The vertex angle of an isosceles triangle is 20° less than the sum of the base angles. Which system of equations can be used to

WINSTONCH [101]

The answer to the above question can be explained as under -

We know that, the sum of angles of triangle is 180°.

So, vertex angle plus base angles are equal are equal to 180°.

Let the vertex angle be represented by "v" and base angles be represented by "b".

Thus, v + b + b = 180°

So, v + 2b = 180°

Next, the question says, the vertex angle is 20° less than the sum of base angles.

Thus, 2b - 20° = v

<u>Thus, we can conclude that the correct option is A) v + 2b = 180°, 2b - 20° = v</u>

6 0

3 years ago

Given m||n, find the value of x.<br> +<br> (5x+16)<br> mm<br> (6x-7)

kupik [55]

Based on the definition of congruent angles, the value of x is: 23.

<h3>What are Congruent Angles?</h3>

Congruent angles have the same measure. Examples of angles that are congruent are:

Alternate interior angles
Alternate exterior angles
Corresponding angles

Thus:

(5x + 16) = (6x - 7) -- congruent angles

Combine like terms

5x - 6x = -16 - 7

-x = -23

x = 23

Therefore, based on the definition of congruent angles, the value of x is: 23.

Learn more about congruent angles on:

brainly.com/question/1675117

5 0

2 years ago

Quadrilateral KMPT is dilated by a scale factor of 3/4 to create K'M'P'T'. The perimeter of quadrilateral KMPT is x units. What

777dan777 [17]

Answer:

B) $\frac{3}{4}$ x units

Step-by-step explanation:

Let quadrilateral KMPT be a rectangle with dimensions 12 units by 8 units. Then its perimeter would be equal to:

Perimeter of a rectangle = 2 (l + b)

where: l is the length = 12 units and b is the breadth = 8 units. So that:

Perimeter of KMPT = 2 (12 + 8)

= 40 units

Dilating KMPT by a scale factor of $\frac{3}{4}$ would create K'M'P'T' of dimensions; $\frac{3}{4}$ × 12 units by $\frac{3}{4}$ × 8 units. Thus, the dimensions of K'M'P'T' would be 9 units by 6 units.

Perimeter of K'M'P'T' = 2 (l + b)

= 2(9 + 6)

= 30 units

Comparing the perimeters of KMPT and K'M'P'T', the perimeter of K'M'P'T' would be $\frac{3}{4}$ × perimeter of KMPT.

Therefore, if the perimeter of KMPT is x units, then;

perimeter of K'M'P'T' = $\frac{3}{4}$ * x units

= $\frac{3}{4}$ x units

6 0

3 years ago

3x/8-1=5/8 How do I start to find out the answer to this equation?