Which graph shows the solution to the system of linear inequalities? y < 2x – 5 y > –3x + 1
2 answers:
Answer:
The graph in the attached figure
Step-by-step explanation:
we have
----> inequality A
The solution of the inequality A is the shaded area below the dashed line
The slope of the dashed line A is positive m=2
The y-intercept of the dashed line A is (0,-5)
The x-intercept of the dashed line A is (2.5,0)
----> inequality B
The solution of the inequality B is the shaded area above the dashed line
The slope of the dashed line B is negative m=-3
The y-intercept of the dashed line B is (0,1)
The x-intercept of the dashed line B is (1/3,0)
The solution of the system of inequalities is the shaded area between the two dashed lines
using a graphing tool
The graph in the attached figure
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1/3 ln(<em>x</em>) + ln(2) - ln(3) = 3
Recall that , so
ln(<em>x</em> ¹ʹ³) + ln(2) - ln(3) = 3
Condense the left side by using sum and difference properties of logarithms:
Then
ln(2/3 <em>x</em> ¹ʹ³) = 3
Take the exponential of both sides; that is, write both sides as powers of the constant <em>e</em>. (I'm using exp(<em>x</em>) = <em>e</em> ˣ so I can write it all in one line.)
exp(ln(2/3 <em>x</em> ¹ʹ³)) = exp(3)
Now exp(ln(<em>x</em>)) = <em>x </em>for all <em>x</em>, so this simplifies to
2/3 <em>x</em> ¹ʹ³ = exp(3)
Now solve for <em>x</em>. Multiply both sides by 3/2 :
3/2 × 2/3 <em>x</em> ¹ʹ³ = 3/2 exp(3)
<em>x</em> ¹ʹ³ = 3/2 exp(3)
Raise both sides to the power of 3:
(<em>x</em> ¹ʹ³)³ = (3/2 exp(3))³
<em>x</em> = 3³/2³ exp(3×3)
<em>x</em> = 27/8 exp(9)
which is the same as
<em>x</em> = 27/8 <em>e</em> ⁹