Answer:
Step-by-step explanation:
4x - 3y = 1
x + 3y = 0
Req To Solve With Elimination:
Make Them Equal:
-> 4x - 3y = 1
-> 4x + 4 . 3y = 0
Simplify:
-> 4x - 3y = 1
-> 4x + 12y = 0
-> 4x - 4x - 3y - 12y = 1
-> -3y - 12y = 1
-> -15y = 1
->
->
->
->
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Answer:
3, 6, 9, 12 is not geometric
Step-by-step explanation:
A geometric progression has a common ratio r between consecutive terms.
3, 6, 9 , 12
has a common difference of 3 between terms and is arithmetic
1, 5, 25, 125
r = 5 ÷ 1 = 25 ÷ 5 = 125 ÷ 25 = 5 ← geometric
4, 8, 16, 32
r = 8 ÷ 4 = 16 ÷ 8 = 32 ÷ 16 = 2 ← geometric
2, 6, 18, 54
r = 6 ÷ 2 = 18 ÷ 6 = 54 ÷ 18 = 3 ← geometric
Step-by-step explanation:
all work is pictured and shown
Answer:
side CB
Step-by-step explanation:
draw triangles ABC and ACD next to each other
The longer leg of the triangle ABC is CB, which corresponds with the longest leg of ACD, which is side CD
Given that the equation to find the height of the firework is
h(t) = at² + vt + h₀
with a = -16 ft/s² and v = 128 ft/s. In addition, since the firework starts from the ground, then the initial height, h₀, is equal to 0. Substituting these values, we have
h(t) = -16t² + 128t + 0 = -16t² + 128t
Seeing that h(t) is a quadratic function, then it forms a parabola. To find its maximum height, we can compute for the parabola's vertex.
To find the vertex's x-coordinate, we can use
t = -b/2a = (-128)/(2 · -16) = -128/-32 = 4
Since, it takes 4 seconds for the firework to reach its maximum height, then the maximum height it reaches is equal to h(4). Hence, we have
h(4) = -16(4)² + 128(4) = -16(16) + 512 = 256
Hence, the highest that the firework can reach is equal to 256 ft.
Answer: A. 256 ft