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3 years ago

9

A cereal box has the dimensions of 0.19 m ´ 0.28 m ´ 0.070 m. if there are 3.28 feet per meter, then what is the volume of the b

ox in cubic feet?

1 answer:

katrin2010 [14]3 years ago

5 0

0.13 cubic feet. You take all of the three numbers (0.19m,0.28m, and 0.070m) and multiply them.

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I need help on this quick

Pachacha [2.7K]

Answer:

The hypotenuse to the nearest tenth is 8.1

Step-by-step explanation:

We can use the Pythagorean theorem to solve

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

Let a be the x leg and b be the y leg

a = 7 units

b= 4 units

7^2 + 4^2 = c^2

49+ 16 = c^2

65 = c^2

Take the square root of each side

sqrt(65) = sqrt(c^2)

8.062257748 =c

To the nearest tenth

8.1 =c

7 0

3 years ago

Which number line is it?

Allushta [10]

Answer is A. first one...

P = -3
G = 3

P = -G = -(3) = -3

0 0

3 years ago

For a snack, sander ate a plum with 32 calories and several strawberries with 4 calories each. If the total number of calories i

muminat

Answer:

6 strawberries

You subtract 32 from 56, which gives you 24. Then, if one strawberry is 4 calories, you can eat 6 of them to gain 24 calories.

32 + 24 = 56 ... So one plum (32) and six strawberries (4+4+4+4+4+4) gives you 56 calories, which is the total. That's how you can check your work.

Answer: 6

4 0

3 years ago

The amount of lateral expansion (mils) was determined for a sample of n = 8 pulsed-power gas metal arc welds used in LNG ship co

Alona [7]

Answer:

95% Confidence interval for the variance:

$3.6511\leq \sigma^2\leq 34.5972$

95% Confidence interval for the standard deviation:

$1.9108\leq \sigma \leq 5.8819$

Step-by-step explanation:

We have to calculate a 95% confidence interval for the standard deviation σ and the variance σ².

The sample, of size n=8, has a standard deviation of s=2.89 miles.

Then, the variance of the sample is

$s^2=2.89^2=8.3521$

The confidence interval for the variance is:

$\dfrac{ (n - 1) s^2}{ \chi_{\alpha/2}^2} \leq \sigma^2 \leq \dfrac{ (n - 1) s^2}{\chi_{1-\alpha/2}^2}$

The critical values for the Chi-square distribution for a 95% confidence (α=0.05) interval are:

$\chi_{0.025}=1.6899\\\\\chi_{0.975}=16.0128$

Then, the confidence interval can be calculated as:

$\dfrac{ (8 - 1) 8.3521}{ 16.0128} \leq \sigma^2 \leq \dfrac{ (8 - 1) 8.3521}{1.6899}\\\\\\3.6511\leq \sigma^2\leq 34.5972$

If we calculate the square root for each bound we will have the confidence interval for the standard deviation:

$\sqrt{3.6511}\leq \sigma\leq \sqrt{34.5972}\\\\\\1.9108\leq \sigma \leq 5.8819$

6 0

3 years ago

How do I find value of X

pashok25 [27]

Answer:

147°

Step-by-step explanation:

106°+139°+126°+141°+112°+129°+x =900°

753°+x = 900°

x = 900°-753°

x= 147° (sum of the interior angles of a heptagon=900°)

4 0

3 years ago