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Umnica [9.8K]
3 years ago
15

What is the greatest common factor of 25 and 75​

Mathematics
2 answers:
Deffense [45]3 years ago
4 0

Answer:

25

Step-by-step explanation:

25 is the largest number that goes into both 25 and 75

ch4aika [34]3 years ago
3 0
It’s five that’s easy
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Answer:

(205-9x) times15

Step-by-step explanation:

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3 years ago
What is one half ( 1/2 ) squared?
lorasvet [3.4K]

Answer:

(\frac{1}{2} )^{2} =\frac{1^2}{2^2} = \frac{1} {4}}

When squaring a fraction, square both numerator AND denominator

7 0
3 years ago
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<img src="https://tex.z-dn.net/?f=if%20%5C%3A%20100%20%7B%20%5C%3A%20%20%7D%5E%7B2%7D%20%20%5C%3A%20%20%3D%20251p%20%5C%3A%20sol
Nikolay [14]
= 39.84
:
100^2=251
10000=251
ℎ
251 ℎ
10000/251=251/251
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8 0
3 years ago
Read 2 more answers
Kai picked 7 times as many blueberry as Nico.together they picked 297
Helga [31]

Answer:

Step-by-step explanation:

You need to specify what the goal of the problem is.

If Kai picked 7 times as many blueberries as Nico, then:

n + 7n + 297, or

8n = 297.  Unfortunately, 8 does not divide evenly into 297, and we certainly are not interested in picking fractional blueberries.

If the problem mentioned 296 instead of 297 total blueberries, then

Nico (n) picked 47 blueberries and Kai picked 7 times that many, or 329.

5 0
3 years ago
How many Solutions does this system have? (1 point)
mixas84 [53]

The given system of equation that is 2x+y=3 and 6x=9-3y has infinite number of solutions.

Option -C.

<u>Solution:</u>

Need to determine number of solution given system of equation has.

\begin{array}{l}{2 x+y=3} \\\\ {6 x=9-3 y}\end{array}

Let us first bring the equation in standard form for comparison

\begin{array}{l}{2 x+y-3=0} \\\\ {6 x+3 y-9=0}\end{array}

\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}} \neq \frac{c_{1}}{c_{2}}

To check how many solutions are there for system of equations a_{1} x+b_{1} y+c_{1}=0 \text{ and }a_{2} x+b_{2} y+c_{2}=0, we need to compare ratios of \frac{a_{1}}{a_{2}}, \frac{b_{1}}{b_{2}} \text { and } \frac{c_{1}}{c_{2}}

In our case,  

a_{1} = 2, b_{1}= 1\text{ and }c_{1}= -3

a_{2}  = 6, b_{2} = 3,\text{ and }c_{2} = -9

\begin{array}{l}{\Rightarrow \frac{a_{1}}{a_{2}}=\frac{2}{6}=\frac{1}{3}} \\\\ {\Rightarrow \frac{b_{1}}{b_{2}}=\frac{1}{3}} \\\\ {\Rightarrow \frac{c_{1}}{c_{2}}=\frac{-3}{-9}=\frac{1}{3}} \\\\ {\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}=\frac{1}{3}}\end{array}

As \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}, so given system of equations have infinite number of solutions.

Hence, we can conclude that system has infinite number of solutions.

5 0
3 years ago
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