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4 years ago

Solve for a h = a/4

Mathematics

1 answer:

aivan3 [116]4 years ago

8 0

Answer:

a=4h

Steps:

4h=a swap the sides

a=4h

So , a=4h

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Use Long Division to find the answer. Please show all steps!

ValentinkaMS [17]

Answer:

The answer to your question is 2x² + 3x + Remainder (17x - 7)/ ( 2x⁴ + 3x³ - 4x² + 5x - 7)

Step-by-step explanation:

2x² + 3x

x² - 4 2x⁴ + 3x³ - 4x² + 5x - 7

-2x⁴ + 4x²

0 + 3x³ + 0 + 5x

- 3x³ +12x

0 +17x - 7

Quotient = 2x² + 3x

Remainder = 17x - 7

Solution = 2x² + 3x + (17x - 7)/ ( 2x⁴ + 3x³ - 4x² + 5x - 7)

Process

1.- Divide the first term of the divident by the first term of the divisor and place the result above the first term of the divident.

2.- Multiply the result of the division (2x²) by the first term of the divisor and change the sign of the result.

3.- Multiply the result (2x²) by the second term of the divisor and place the result below the like term.

4.- Add the results.

5.- Continue with this process until the remainder be lower than the divisor.

5 0

4 years ago

Someone please help I genuinely don’t understand

mart [117]

Answer:

Step-by-step explanation:

2) l = 9 cm

b = 7 cm

h = 3 cm

Surface Area= 2*(lb + bh + hl)

=2*(9*7 + 7*3 + 3*9)

=2*(63 + 21 + 27)

= 2 * 111

= 222 cm²

7 0

3 years ago

I need help what is 145 marked up 175%

Ede4ka [16]

First you multiply 145 by 01.75 to get how much you add to the total. You add 253.75 to 145 and get 398.75 as the answer

7 0

3 years ago

"(b) use part (a) to find a power series for f(x) = 1 (4 + x)3 ."

Firdavs [7]

Assuming

$f(x)=\dfrac1{(4+x)^3}$

Recall that for $|x|$ ,

$\displaystyle\sum_{n\ge0}x^n=\frac1{1-x}$

Denote the above by $s(x)$ . Then

$s'(x)=\displaystyle\sum_{n\ge1}nx^{n-1}=\frac1{(1-x)^2}$
$s''(x)=\displaystyle\sum_{n\ge2}n(n-1)x^{n-2}=\frac2{(1-x)^3}$

Now,

$\dfrac1{(4+x)^3}=\dfrac1{4^3}\dfrac1{\left(1-\left(-\frac x4\right)\right)^3}=\dfrac1{2^7}\dfrac2{\left(1-\left(-\frac x4\right)\right)^3}$

which means we have

$f(x)=\dfrac1{2^7}s''(x)=\dfrac1{128}\displaystyle\sum_{n\ge2}n(n-1)\left(-\frac x4\right)^{n-2}$

which is valid for $\left|-\dfrac x4\right|$ , or $|x|$ .

4 0

3 years ago

What value of x makes the equation true? 1/2(4x−5)+52=10

Anon25 [30]

Answer:

x = -19.75

Step-by-step explanation:

$\frac{1}{2}(4x-5) +52 =10$