I need help with B and C
1 answer:
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The first term is 612.
The common ratio is 1.08 and
The recursive rule is
<u>Step-by-step explanation:</u>
the question to the problem is to write the values of the first term, common ratio, and expression for the recursive rule.
<u>The first term :</u>
In geometric sequence, the first term is given as .
⇒
Now, the geometric sequence follows as 612, 661, ........
<u>The common ratio (r) :</u>
It is the ratio between two consecutive numbers in the sequence.
Therefore, to determine the common ratio, you just divide the number from the number preceding it in the sequence.
⇒ r = 661 divided by 612
⇒ r = 1.08
<u>To find the recursive rule :</u>
A geometric series is of the form a,ar,ar2,ar3,ar4,ar5........
Here, first term and other terms are obtained by multiplying by r.
- Observe that each term is r times the previous term.
- Hence to get nth term we multiply (n−1)th term by r .
The recursive rule is of the form
This is called recursive formula for geometric sequence.
We know that r = 1.08 and = 612.
To find the second term , use the recursive rule
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