There are 2 variables in this problem. One variable is the class number and other variable is the participation in extracurricular activities. Each variable has further two categories. There are two classes: Class 10 and 11. And students either participate or do not participate in extracurricular activities, which makes 2 categories.
The best approach to solve this question is to build a table and start entering the given information in it. When the given data has been entered fill the rest on basis of the data you have.
18 students from grade 11 participate in at least one Extracurricular activities. This means the rest students i.e. 22 students from grade 11 do not participate in Extracurricular activities.
32 students from grade 10 participate in at least one Extracurricular activities. This means total students who participate in at least one Extracurricular activities are 18 + 32 = 50 students.
The rest 50 students do not participate in at least one Extracurricular activities. From these 22 are from class 11. So the rest i.e. 28 are from class 10.
True? I dont know what you're trying to ask. if you're asking whether or not it's true, it is.
Answer:
in my knowledge
Option A..
Step-by-step explanation:
This is an arithmetic sequence since there is a common difference between each term. ... This is the formula of an arithmetic sequence.
Answer:
Answer is 225.
We have to find the sum of 15 terms of the series
sigma 1 to 15 (2n-1)
This can be split as per summation terms as
sigma 2n - sigma 1
sigma 2n can again be simplified by taking 2 outside
sigma 2n= 2 times sum of natural numbers of 1 to 15
= 2(15)(16)/2= 240
sigma 1= 1+1+...15 times= 15
Hence final answer is
= 2 times sigma n - (n) = 240-15 = 225.
Step-by-step explanation:
