Answer:
In ∆ABD and ∆ACD
<BAD =<CAD ( each are half of <A )
<D=<D ( each equal to 90°)
AD = AD ( common)
So ∆ ABD is congruent to ∆ ACD.
Then AB =AC (by C.P.C.T)
Hence,∆ABC is an iso - sceles triangle.
When solving for a variable, you get the variable you're trying to solve for on one side and everything to the opposite of that variable.
We have the equation <span>5w + 9z = 2z + 3w.
Usually the variable we're solving for we want on the left. But it's fine to have it on the right side, too.
Let's subtract 9z from the left-hand side. That way, the 5w will be alone on the left-hand side.
And remember, anything we do on one side we do to the other side.
</span><span>5w + 9z - 9z = 2z + 3w - 9z
</span><span>5w = -7z + 3w
The 3w term on the right-hand side needs to be removed. So, subtract each side by 3w.
5w - 3w = -7z + 3w - 3w
2w = -7z
Now, we need to divide each side by 2 to see what the w variable is equal to.
2w / 2 = -7z / 2
w = -7z / 2 or w = -3.5z
So, w is equal to -3.5z.
</span>
Answer:
add an answer bro
Step-by-step explanation:
Answer:
- m = (2-(-2))/(2-(-2)) = 4/4 = 1
- y +2 = 1(x +2)
Step-by-step explanation:
The point-slope form of the equation for a line with slope m through point (x1, y1) is ...
y -y1 = m(x -x1)
To find the slope of the line, find the ratio of the difference in y-values of the points to the difference in corresponding x-values. Here, the slope is ...
m = (2 -(-2))/(2 -(-2)) = 4/4 = 1 . . . work to compute slope
The problem statement tells you x1 = -2, y1 = -2. Putting the numbers in to the point-slope form gives ...
y -(-2) = 1(x -(-2))
y + 2 = x + 2 . . . equation form with m, (x1, y1) filled in
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The answer at the top leaves the slope shown as 1. We don't know how much simplification you are expected to do. Obviously, this <em>could</em> be simplified to y=x, but then the use of (-2, -2) for the point would not be obvious.
Answer:
57
Step-by-step explanation:
range = biggest - smallest
91 - 34 = 57
range = 57
