Question

2log(x-3)+1=5 can someone explain how to solve for x?

Answer 1

$\bf 2log(x-3)+1=5\iff 2log_{10}(x-3)+1=5\\\\\\ 2log_{10}(x-3)=4 \\\\\\ log_{10}(x-3)=\cfrac{4}{2}\implies log_{10}(x-3)=2\\\\ -----------------------------\\\\ {{ a}}^{log_{{ a}}x}=x\impliedby \textit{using this cancellation rule}\\\\ -----------------------------\\\\ 10^{\cfrac{}{}log_{10}(x-3)}=10^2\implies x-3=10^2\implies x=100+3$