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Alex Ar [27]
4 years ago
11

2log(x-3)+1=5 can someone explain how to solve for x?

Mathematics
1 answer:
Brums [2.3K]4 years ago
5 0
\bf 2log(x-3)+1=5\iff 2log_{10}(x-3)+1=5\\\\\\ 2log_{10}(x-3)=4
\\\\\\
log_{10}(x-3)=\cfrac{4}{2}\implies log_{10}(x-3)=2\\\\
-----------------------------\\\\
{{  a}}^{log_{{  a}}x}=x\impliedby \textit{using this cancellation rule}\\\\
-----------------------------\\\\
10^{\cfrac{}{}log_{10}(x-3)}=10^2\implies x-3=10^2\implies x=100+3
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Step-by-step explanation:

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Can someone please give me the (Answers) to this? ... please ...
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b.) We are given two triangles with a pair of corresponding, congruent sides. We need to have a pair of corresponding, congruent angles, another pair of corresponding, congruent sides to follow SAS. Therefore, we would need to know the angle measures of angles UVW and KVM. We know that they are vertical angles, so they are indeed congruent. Now, we would need to know the side lengths of sides WV and VM. If those sides are congruent, then we have a pair of corresponding, congruent sides, a pair of corresponding, congruent angles, and another pair of corresponding, congruent sides, making SAS.

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Leno4ka [110]

Answer:

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<u>Step 1:  Convert to improper fractions</u>

2 2/4 = 2 * 4/4 + 2/4 = 8/4 + 2/4 = 10/4

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<u>Step 2:  Make common denominator</u>

10/4 is ok

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<u>Step 3:  Combine </u>

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Answer: 16/4

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