Let x be the length and y be the width of a rectangle.
Area = xy
When x and y are doubled
Length = 2x and Width = 2y
Area = 2x x 2y
Area = 4xy
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Answer: When the dimension is doubled, the area is 4 times the original.
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Answer:
x=6
Step-by-step explanation:
x + 6 = x + x original problem
x + 6 = 2x combine like terms
-x = -x subtract x from both sides to have like terms on each side
6 = x solution
Answer:
14
Step-by-step explanation:
Shown in picture above.
Given that Jordan has a new puppy and she wants to put a fence around part of her yard to cover an area of 200 square feet.
Now we have to find what dimensions (length x width) should she make the rectangular area. None of the length or width are given so there can be lots of answers.
Since area is rectangular and we know that rectangle has different value of length and width so we just need to find two factors of given area 200 square feet.
For example 20 times 10 is 200.
So the dimension of the rectangular area will be:
Length = 20 feet and width = 10 feet
Now perimeter of the rectangle is given by formula:
Perimeter = 2(length+width) = 2(20+10)=2(30)=60
Hence perimeter is 60 feet.
