All categories

2 years ago

3-3k+7k=5b solve for k

Mathematics

1 answer:

DaniilM [7]2 years ago

5 0

$3-3k+7k=5b \\\\ 3+4k=5b \\\\ 4k=5b-3 \\\\ \boxed{k=\frac{5b-3}{4}}$

You might be interested in

Find the distance CA

katrin [286]

C' ( 0, 3)

A' ( 2 , 1)

C'A' = CA

C'A' = √(2^2 + 2^2) = √8 = 2√2

C'A' = CA = 2√2

3 0

2 years ago

A researcher wants to estimate the percentage of all adults that have used the Internet to seek pre-purchase information in the

Lubov Fominskaja [6]

Answer:

The required sample size for the new study is 801.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

25% of all adults had used the Internet for such a purpose

This means that $\pi = 0.25$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

What is the required sample size for the new study?

This is n for which M = 0.03. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.96\sqrt{\frac{0.25*0.75)}{n}}$

$0.03\sqrt{n} = 1.96\sqrt{0.25*0.75}$

$\sqrt{n} = \frac{1.96\sqrt{0.25*0.75}}{0.03}$

$(\sqrt{n})^2 = (\frac{1.96\sqrt{0.25*0.75}}{0.03})^2$

$n = 800.3$

Rounding up:

The required sample size for the new study is 801.

4 0

2 years ago

Hey! please help i’ll give brainliest

Bess [88]

Answer:

all of these

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Two consecutive perfect squares have a difference of $99$. what is the value of the larger perfect square?

Fofino [41]

Answer:

2500

Step-by-step explanation:

Let the first square number be $x^2$ then the next square number is $(x+1)^2$ .

The difference between these two consecutive numbers is 99.

This implies that:

$(x+1)^2-x^2=99$

We expand to get:

$x^2+2x+1-x^2=99$

Simplify:

$2x=99-1$

$2x=98$

Divide both sides by 2

$x=49$

Therefore the value of the larger perfect number is

$(49+1)^2=50^2=2500$ .

6 0

2 years ago

A theater group made appearances in two cities. The hotel charge before tax in the second city was $1000 lower than in the first

Artyom0805 [142]

Answer:

Let x = the charge in 1st city before taxes

Let y = the charge in 2nd city before taxes

Set up equation before taxes.

y = x - 1500 eq1

Set up equation for total tax paid.

0.065x + 0.06y = 378.75 eq2

Substitute eq1 into eq2.

0.065x + 0.06(x - 1500) = 378.75

0.065x + 0.06x - 90 = 378.75

0.125x - 90 = 378.75

0.125x = 468.75

x = 3750

Substitute this value of x into eq1.

y = 3750 - 1500

y = 2250

The hotel charge in city one is $3750 and the hotel charge in city two is $2250

3 0

2 years ago