C is wrong...............
Substitute in y= equation into 2nd equation to start.
(2,5)
Step-by-step explanation:
Given problem is to find nearest number,
= 8888888/2915
quotient = 3049
remainder= 1053
Now, 2915-1053 = 1862
8888888+1862 = 8890750
8888888-1053 = 8887835
Two numbers nearest to 8888888 which are exactly divisible by 2915 is 8887835 and 8890750
We can use completing the square.We add 16 and subtract 7 to both sides. Now we get m^2+8m+16=9. The left sides becomes (m+4)^2=9. Taking the square root of both sides and subtracting 4 we get -1 and -7.
