Answer: the variable is p=6 .
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable
1. Regroup terms
x^3 - 6 * 10x^2x-8/ x-3
2. Use product rule
x^3 - 6 * 10x^ 2+1 - 8/ x-3
3. Simplify
x^3 - 6 * 10 x^3 - 8/ x-3
4. Simplify further
x^3 - 60x^3 - 8/ x-3
5. Simplify the last time
-59x^3-8/x-3
Answer:
18,176
Step-by-step explanation:
Figure out an easier thing to do: 1000 - 2021 = 9,797.
Therefore, our answer will be like 9999999999999999999999997979. Out of all of these digits, there are only 2 that arent nines. We know the amount of digits since it's 10^2021 power. We will have one less since we are subtracting 2021. Therefore, 2020 digits in total. Now we know of those 2020 digits, 2 of them are 7, therefore 2018 of them are 9s. That means do 2018(9) + 2(7) = 14 + 18,162 = 18,176.
1 3/6 + 4/6 = 1 7/6 = 2 1/6
Answer:
The probability that a defective rod can be salvaged = 0.50
Step-by-step explanation:
Given that:
A machine shop produces heavy duty high endurance 20-inch rods
On occasion, the machine malfunctions and produces a groove or a chisel cut mark somewhere on the rod.
If such defective rods can be cut so that there is at least 15 consecutive inches without a groove.
Then; The defective rod can be salvaged if the groove lies on the rod between 0 and 5 inches i.e ( 20 - 15 )inches
Now:
P(X ≤ 5) = 
= 0.25
P(X ≥ 15) = 
= 0.25
The probability that a defective rod can be salvaged = P(X ≤ 5) + P(X ≥ 15)
= 0.25+0.25
= 0.50
∴ The probability that a defective rod can be salvaged = 0.50