Hello,
y=2xe^x
y'=2(e^x+xe^x)=2(x+1)e^x
y''=2(e^x+(x+1)e^x)=2(x+2)e^x
x |-infinite -2 0 +infinite
e^x | ++++++++++++++++++
x+2 |------------0 +++++++++++
y'' | -----------0 +++++++++++
y''<0 if x<-2
<span>The interval on which the graph is concave down is (-infinite -2[</span>
An equation is:
2(x+3)-7=9
Distribute the 2
2(x)+2(3) -7=9
2x+6-7=9
Combine like terms
2x-1=9
Add one to both sides
2x-1+1=9+1
2x=10
Divide both sides by two to isolate the variable.
2x/2=10/2
x=m
Answer: g(f(x)) = g(x²-7)=x
Step-by-step explanation:
Answer:
a) see below
b) 40x20 meters
Step-by-step explanation:
Write down what you know:
- The area of the enclosure is length*width, so

- The length of the fencing is 80 meters, so

Now we have to combine these two equations above, and get rid of y in the process.
First rewrite the second as:

Then substitute for y in the first:

b) To maximize A, find the zero of the first derivative:

So y = (80-40)/2 = 20 meters.
Tne znswer ks gonna be 9450 and your welcome