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erica [24]
3 years ago
11

A family has two cars. The first car has a fuel efficiency of

Mathematics
1 answer:
Talja [164]3 years ago
8 0
The first car consumed 21 gallons while the second car consumed 49 gallons. here is the how it's done.
for the first car gallons consumed is 15/50x70= 21 gallons
the second car consumed 35/50x70=49 gallons
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A wire is strung from the top of a pile to a point on the ground. The length of the wire is 100 ft. The angle of depression from
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Step-by-step explanation:

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A random sample of 50 bottles is selected from the production line of a large manufacturing company. The mean weight of the cont
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The population is all bottles in the production line and the sample is the 50 bottles that were selected.

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All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be
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Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

A = a + (A \cap B)

In which a is the probability that a student is proficient in reading but not mathematics and A \cap B is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

B = b + (A \cap B)

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

(A \cup B) + C = 1

In which

(A \cup B) = a + b + (A \cap B)

65% were found to be proficient in both reading and mathematics.

This means that A \cap B = 0.65

78% were found to be proficient in mathematics

This means that B = 0.78

B = b + (A \cap B)

0.78 = b + 0.65

b = 0.13

85% of the students were found to be proficient in reading

This means that A = 0.85

A = a + (A \cap B)

0.85 = a + 0.65

a = 0.20

Proficient in at least one:

(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98

What is the probability that the student is proficient in neither reading nor mathematics?

(A \cup B) + C = 1

C = 1 - (A \cup B) = 1 - 0.98 = 0.02

There is a 2% probability that the student is proficient in neither reading nor mathematics.

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2 years ago
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I believe the answer would be volcanic eruptions.
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Answer what exactly?
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