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3 years ago

the cost of 5 cans of dog food is $4.35. at this price how much do 11 cans of dog food cost explain your reasoning. ASAP

Mathematics

1 answer:

mestny [16]3 years ago

6 0

Answer:

Cost of 11 cans of Dog food is $9.57

Step-by-step explanation:

Cost of 5 cans of dog food = $4.35

So to find out the cost of 11 cans of dog food at the same price, we need to calculate the price of 1 can of dog food.

Calculation for finding out cost of 1 can of dog food

The price $4.35 which is given is the price of 5 cans

So to find the cost of 1 can, we need to divide the given price by 5

5 Cans of dog food = $4.35

1 can of dog food = 4.35 ÷ 5

1 can of dog food = $0.87

Now to find out the price of 11 cans, we will multiply the price of 1 can with 11

Cost of 11 cans = 11 × $0.87

= $9.57

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Based on the histogram, estimate the standard deviation of the distribution.

notka56 [123]

The standard deviation for the distribution will be S=10767.42

<h3>What is standard deviation?</h3>

In statistics, the standard deviation is a measure of the amount of variation or dispersion of a set of values.

The formula for the calculation of standard deviation will be given by

$S=\sqrt{\dfrac{\sum(x-\mu)}{n-1}$

Here S is standard deviation $\mu$ is mean and n is number of the data points.

Mean will be calculated as

$\mu=\dfrac{12000+10000+8000+6000+4000+2000}{8}=\dfrac{42000}{8}=5250$

Now we will calculate standard deviation from the formula

$S=\sqrt{\dfrac{\sum(x-\mu)}{n-1}$

By putting all the values we will get

$S=\sqrt{115937500}$

S=10767.42

Hence the standard deviation for the distribution will be S=10767.42

To know more about standard deviation follow

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3 years ago

The first day of baseball comes in late March, ending in October with the World Series. Does fan support grow as the season goes

svet-max [94.6K]

Answer:

Step-by-step explanation:

Hello!

You need to create a 99% confidence interval for the difference of proportions between fans of baseball polled in March and November.

The parameter to estimate with the interval is ρ₁-ρ₂

Sample 1 (March)

n₁= 1001 adults aged 18 and older.

sample proportion ^ρ₁= 0.44

Sample 2 (November)

n₂= 1001 adults aged 18 and older.

sample proportion ^ρ₂= 0.52

This interval is constructed under a Z distribution, so you need to look in the Z-table for the statistic value:

$Z_{1-\alpha/2}$ = $Z_{0.995}$ = 2.58

The formula for the interval is:

[(^ρ₁-^ρ₂)± $Z_{1-\alpha/2}$ *√^ρ₁(1-^ρ₁) + ^ρ₂(1-^ρ₂)]

n₁ n₂

[(0.44-0.52)±2.58*√0.44*0.56 + 0.52*0.48]

1001 1001

[-0.137;-0.023]

Note: Although proportions take numbers from 0 to 1, keep in mind that this interval was constructed for the difference between two proportions, it's all right to have a negative interval, which means that the proportion of baseball fans in November is significantly bigger.

I hope you have a SUPER day!

6 0

3 years ago

What is the perimeter of the figure in the diagram (round to three decimal places if necessary)?

Y_Kistochka [10]

Perimeter (p) = length around a shape.
So any horizontal sides we can add based upon their length in x-values and any vertical sides we can add based upon their length in y-values. The diagonal sides we can find by the distance formula:
$d = \sqrt{( {(x2 - x1)}^{2} + {(y2 - y1)}^{2} }$
So the bottom base goes from x=1 to x=8, then up 1, right 1, and up from y=3 to y=9, then left from x=9 to x=6, down from y=9 to y=6, left from x=6 to x=3.
So far that is: (8-1)+1+1+(9-3)+(9-6)+(9-6)+(6-3)
= 7+2+6+3+3+3 = 24
Now for the diagonal:
$d = \sqrt{( {(x2 - x1)}^{2} + {(y2 - y1)}^{2}) } \\ = \sqrt{( {(3- 1)}^{2} + {(6 - 2)}^{2} )} \\ = \sqrt{( {2}^{2} + {4}^{2} )} = \sqrt{(4 + 16)} \\ = \sqrt{20} = 2 \sqrt{5} = 4.47$
P = 24 + 4.47 = 28.47
D) 28.472

4 0

3 years ago

Read 2 more answers

Describe how to transform the quantity of the fifth root of x to the seventh power, to the third powerinto an expression with a

tia_tia [17]

If I'm understanding you correctly, you are asking to change x^(7/5) to x^3.
Raise x^(7/5) to the (15/7) power which yields x^3.

7 0

3 years ago

1) solve for w: 3w - 10 = 4w + 5 2) solve for t:6 -2t >18

Gre4nikov [31]

Problem # 1
3w-10=4w+5
(3w-10) + (10-4w) = (4w+5) + (10-4w)
(3w-10) + (-4w+10) = (4w+5) + (-4w +10)
3w-10-4w+10 = 4w +5 -4w +10
3w-4w=15
-w=15
w= -15 (w is negative 15)

problem #2.
6-2t > 18
6-2t-6 > 18-6
-2t > 12
(-1) (-2t) > 12 (-1)
2t > -12
next divide by 2
2t/2 > -12/2
t > -6 (t is greater then negative 6)

5 0

4 years ago