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Dmitrij [34]
3 years ago
5

Luke drives 16 miles from his house to reach a restaurant. Just as he reaches the restaurant, he realizes that he forgot his wal

let. So, he turns around and drives all the way back to his house. On both parts of the trip, he drives at a constant speed of 0.8 mile/minute. Match the number of minutes since Luke started driving from his house to his distance from the house.
Mathematics
2 answers:
zhannawk [14.2K]3 years ago
6 0

Distance between Luke's house and restaurant is 16 m.

Since he drives to the restaurant and back to home, so total distance travelled will be double of 16 m that is 32m.

Speed at which Luke drove is 0.8 miles/minute.

Speed, distance and time can be related by the formula :

speed = \frac{distance}{time}

So in order to find time,

time = \frac{distance}{speed}

time = \frac{32}{0.8}

time = 40 minutes.

Answer: The number of minutes since Luke started driving from his house to his distance from the house is 40 minutes.


Dmitrij [34]3 years ago
3 0

The total distance traveled from his house to the restaurant and then back to his house =16+16= 32 miles.

He drove at the constant speed of 0.8 miles per minute.

Total Time taken = \frac{Distance travled}{Speed}\

==\frac{32}{0.8} =\frac{320}{8} =40 minutes.

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Answer:

y = 3\, \sqrt{5} when x = 9.

Step-by-step explanation:

The question states that y is proportional to \sqrt{x}. In other words, there is a constant a (a \ne 0) such that y = a\, \sqrt{x} for all x \ge 0.

The question also states that y = x when x = 5. Make use of this equality to find the value of a.

Since x = 5 and y = x, it must be true that y = 5. Substitute x = 5\! and y = 5\! into the equation y = a\, \sqrt{x} and solve for a:

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\begin{aligned} y &= \sqrt{5} \, (\sqrt{9}) \\ &= \sqrt{5} \times 3 \\ &= 3\, \sqrt{5}\end{aligned}.

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