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Dmitrij [34]
4 years ago
5

Luke drives 16 miles from his house to reach a restaurant. Just as he reaches the restaurant, he realizes that he forgot his wal

let. So, he turns around and drives all the way back to his house. On both parts of the trip, he drives at a constant speed of 0.8 mile/minute. Match the number of minutes since Luke started driving from his house to his distance from the house.
Mathematics
2 answers:
zhannawk [14.2K]4 years ago
6 0

Distance between Luke's house and restaurant is 16 m.

Since he drives to the restaurant and back to home, so total distance travelled will be double of 16 m that is 32m.

Speed at which Luke drove is 0.8 miles/minute.

Speed, distance and time can be related by the formula :

speed = \frac{distance}{time}

So in order to find time,

time = \frac{distance}{speed}

time = \frac{32}{0.8}

time = 40 minutes.

Answer: The number of minutes since Luke started driving from his house to his distance from the house is 40 minutes.


Dmitrij [34]4 years ago
3 0

The total distance traveled from his house to the restaurant and then back to his house =16+16= 32 miles.

He drove at the constant speed of 0.8 miles per minute.

Total Time taken = \frac{Distance travled}{Speed}\

==\frac{32}{0.8} =\frac{320}{8} =40 minutes.

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lbvjy [14]

Answer:

(x - 4)³

Step-by-step explanation:

"The cube of x" would be x³.  The difference of a number and 4 would be x - 4.

Therefore, "the cube of the difference of a number and 4" would be

(x - 4)³

6 0
3 years ago
What is bigger 11/15 or 8/9?
levacccp [35]

8/9 = 0.88...

11/15 = 0.733...

8/9 is bigger

6 0
3 years ago
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Sergeeva-Olga [200]

The cost of the sheets is less for the second example, the second example is the better deal.

Consider the first example:

Here, A brand of sheets is on sale for “Buy one get one at 50% off”. If each sheet costs $18.00.

So, the value of the first sheet will be $18,

And since the other sheet is at 50% off .

That is it will be half of the original value

= 50/100 * 18

=9

Therefore, the cost of two sheets

=$18 + $9

= $27.

So, Six sheets will cost

=$27+$27+$27

= $81

Cost of six sheets will be $81

Now, consider the second example

In the second example sheets are 30% off.

So, 30% of 18

= $6.

Subtract that value from 18 and you will get $12.

So, cost of one sheet =  $12.

cost of 6 sheet

=  $12×6

= $72  

In the first example, Six sheets costs $81, while in the second example six sheets cost $72.

Since the cost is less for the second example. So, the second example is the better deal.

4 0
2 years ago
Please helppppppppppp
muminat

surface area = (2)(5)(13)+(13)(10)+(12)(10)

6 0
3 years ago
Find the lengths and slopes of the diagonals to name the parallelogram. Choose the most specific name. E (-2, -4), F(0, -1), G(-
Kay [80]

Answer:

1) d) Square

2) Proofs that PWRS is a rhombus are

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Step-by-step explanation:

The given points (x, y) of the parallelogram are;

E(-2, -4), F(0, -1), G(-3, 1), H(-5, -2)

The slope, m, of the segments are found as follows;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

By computation, the slope of segment EF = 1.5

The slope of segment FG = -0.67

The slope of segment GH = 1.5

The slope of segment HE = -0.67

Therefore, EF is parallel to GH and FG is parallel to HE

The length of the sides are;

\sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

By computation, the length of segment EF = 3.61

The length of segment FG = 3.61

The length of segment GH = 3.61

The length of segment HE = 3.61

The diagonals are;

EG and FH

The length of segment EG = 5.099

The length of segment FH = 5.099

Therefore, the diagonals are equal and the parallelogram is a square

2) The given dimensions are;

P(-1, 3), Q(-2, 5), R(0, 4), S(1, 2)

A rhombus has all sides equal

The length of segment PQ = 2.24

The length of segment QR = 2.24

The length of segment RS = 2.24

The length of segment PS = 2.24

The diagonals are;

QS and PR

The length of segment QS = 4.24

The length of segment PR = 1.41

The slope of segment QR = -0.5

The slope of segment PS = -0.5

The slope of segment RS = -2

The slope of segment QP = -2

Therefore, QS≠QR the parallelogram is a rhombus

The correct option ;

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Where there are acute angles in parallelogram PQRS, then the correct option is d) Length of QR and PS is 2.2 and Length of RS and QP is 2.2

8 0
3 years ago
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