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Varvara68 [4.7K]
3 years ago
12

Factor using the x method ( please do not answer without showing work )

Mathematics
2 answers:
muminat3 years ago
8 0

Answer:

5(x + 10)(10x - 3)

Step-by-step explanation:

We are factoring

50x^{2} + 485x - 150

So:

((2•5^2x^2) +  485x) -  150

Pull like factors :

50x^2 + 485x - 150  =   5 • (10x^2 + 97x - 30)

Factor

 10x^2 + 97x - 30

Step-1: Multiply the coefficient of the first term by the constant   10 • -30 = -300

Step-2: Find two factors of  -300  whose sum equals the coefficient of the middle term, which is 97.

-300    +    1    =    -299

     -150    +    2    =    -148

     -100    +    3    =    -97

     -75    +    4    =    -71

     -60    +    5    =    -55

     -50    +    6    =    -44

     -30    +    10    =    -20

     -25    +    12    =    -13

     -20    +    15    =    -5

     -15    +    20    =    5

     -12    +    25    =    13

     -10    +    30    =    20

     -6    +    50    =    44

     -5    +    60    =    55

     -4    +    75    =    71

     -3    +    100    =    97

Step-3: Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -3  and  100

                    10x^2 - 3x + 100x - 30

Step-4: Add up the first 2 terms, pulling out like factors:

                   x • (10x-3)

             Add up the last 2 terms, pulling out common factors:

                   10 • (10x-3)

Step-5: Add up the four terms of step 4:

                   (x+10)  •  (10x-3)

            Which is the desired factorization

Thus your answer is

5(x + 10)(10x - 3)

likoan [24]3 years ago
3 0

Answer:

\displaystyle  \rm 5({x}^{}  +   10)( 10x - 3)

Step-by-step explanation:

we would like to factor out the following expression:

\displaystyle   {50x}^{2}  + 485x - 150

notice that, in every term there's a common factor of 5 thus factor it out:

\displaystyle  5( {10x}^{2}  + 97x - 30)

now we have to rewrite the middle term as sum or substraction of two different terms in that case 100x-3x can be considered:

\displaystyle  5( {10x}^{2}  + 100 - 3x - 30)

factor out 10x:

\displaystyle  5( 10({x}^{2}  + 10)- 3x - 30)

factor out -3:

\displaystyle  \rm 5( 10x({x}^{}  + 10)- 3(x  + 10))

group:

\displaystyle  \rm 5({x}^{}  +   10)( 10x - 3)

and we are done!

hence,

our answer is B)

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