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3 years ago

12

Help please, I have a test!! HELP!!!!!!

1 answer:

aniked [119]3 years ago

8 0

Answer: its e

Step-by-step explanation:

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Solve the equation for y.<br> 8x – 9y = 11

pav-90 [236]

8x-9y=11

First you move the 8x because you have to leave the 9y alone

8x-9y=11
-8x -8x

-9y=11-8x

Now you have to move the -9, so the inverse of multiplying is dividing so you divide -9.

-9y/-9= 11/-9 -8x/-9

since you can't have negative as a denominator it would be:

y= -11/9+8x/9

<span>You have to change the signs</span>

3 0

3 years ago

What is the area of triangle FGH? Round your answer to the nearest tenth of a square centimeter.

Misha Larkins [42]

Answer:

Step-by-step explanation:

8 0

3 years ago

Help please ASAP thank you!! your awesome if you help

12345 [234]

Answer:

Perimeter=56 units

Area =196 square unites

Step-by-step explanation:

The diagonal would be 14√2.

The formula for area using the diagonal is 1/2d².

1/2x(14√2)²=1/2x196x2=196

For perimeter, s²+s²=392

2s²=392

s²=196

s=√196

s=14

14x4=56

6 0

3 years ago

After the first term in a sequence, the ratio of each term to the preceding term is r. If the first term is a, what is the third

irinina [24]

Answer:

The 3rd term is

$ar^2$

Step-by-step explanation:

From the given information, the first term of the sequence is

$a_1=a$

The common ratio of the sequence is

$r$

The explicit formula for a geometric sequence is :

$a_n=a_1(r^{n-1})$

To find the third term, we put n=3 to get:

$a_n=a(r^{3-1})$

This simplifies to:

$a_3=ar^2$

7 0

3 years ago

A guitar string is plucked at a distance of 0.6 centimeters above its resting position and then released, causing vibration. The

liubo4ka [24]

Answer:

The equation that represents the motion of the string is given by:

$y =Ae^{-kt}\cos(2\pi ft)$ .....[1] where t represents the time in second.

Given that: A = 0.6 cm (distance above its resting position) , k = 1.8(damping constant) and frequency(f) = 105 cycles per second.

Substitute the given values in [1] we get;

$y =0.6e^{-1.8t}\cos(2\pi 105t)$

or

$y =0.6e^{-1.8t}\cos(210\pi t)$

(a)

The trigonometric function that models the motion of the string is given by:

$y =0.6e^{-1.8t}\cos(210\pi t)$

(b)

Determine the amount of time t that it takes the string to be damped so that $-0.24\leq y \leq0.24$

Using graphing calculator for the equation

$y =0.6e^{-1.8x}\cos(210\pi x)$

let x = t (time in sec)

Graph as shown below in the attachment:

we get:

the amount of time t that it takes the string to be damped so that $-0.24\leq y \leq0.24$ is, 0.5 sec

4 0

3 years ago