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user100 [1]
4 years ago
11

richard works at an ice cream shop. regular cones get 2 scoops of ice cream, large cones get 2 scoops. richard scooped 234 regul

ar cones and 156 large cones. ones scoop of ice cream is 3 ounces. a tub of ice cream weighs 10 pounds, how many tubs of ice cream were used?
Mathematics
1 answer:
Tanya [424]4 years ago
5 0

Answer:

So both cones get two scoops? large and regular?

Step-by-step explanation:

10lbs=160oz

Multiply the total number of scoops for both sized by 3 then divide it by 160. This will give you the number of tubs. With the numbers you gave me the answer would be 14.625 Tubs but you cant have half a tub so 14

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A stack of cards consists of seven red and four blue cards. A second stack of cards consists of eleven red cards. A stack is sel
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0.1733 = 17.33% probability the first stack was selected.

Step-by-step explanation:

To solve this question, it is needed to understand conditional probability, and the hypergeometric distribution.

Hypergeometric distribution:

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In which:

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N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

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Conditional probability:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

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P(A \cap B) is the probability of both A and B happening.

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Probability of all red cards for the first stack:

For this, we use the hypergeometric distribution, as the cards all chosen without replacement.

7 + 4 = 11 cards, which means that N = 11.

7 red, which means that k = 7

3 are chosen, which means that n = 3

We want all red, so we find P(X = 3).

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 3) = h(3,11,3,7) = \frac{C_{7,3}*C_{4,0}}{C_{11,3}} = 0.2121

Conditional probability:

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Event B: From the first stack.

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P(A) = 0.2121*0.5 + 1*0.5 = 0.60605

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What is the probability the first stack was selected?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.105}{0.60605} = 0.1733

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