Two lines are parallel if they intersect.
A regular quadrilateral prism has 12 edges. It is given perimeter of the base 32 cm. Length of each edge of base will be 32÷4=8 cm. The 4 edges at the top will also have the same number of edges that is 4 with measure 8cm each.
Given: The height of the prism is 2 times greater than the length of the base edge.Height of prism = 2(8)= 16cm. Number of edges with measure 16 cm is 4.
Sum of all the 12 edges= 8+8+8+8+16+16+16+16+8+8+8+8=128 cm.
<span>A=P(1+rn)nt
A=200(1+.02)^3
A=200(1.02)^3
A=200(1.061208)
A=</span><span>212.2416
which u round to 212.24</span>
16 * 4 + 7 * 8
64 + 56
120
Answer: 120 students
