Answer: The amount is $14794.39 and the interest is $9794.39
Step-by-step explanation: If you deposit <em><u>$5000</u></em><u> </u>into an account paying <em><u>7.5%</u></em> annual interest compounded yearly , how much money will be in the account after <em><u>15 years</u></em>?
To find amount we use formula:
A-P(1+r/n) n*t
A = total amount
P = principal or amount of money deposited,
r = annual interest rate
n = number of times compounded per year
t = time in years
P=$5000, r=7.5, n=1 and, t=15 years
After plugging the given information we have
A= $5000 (1+0.075/1)^1.15
A= 5000 *1.075^15
A=14794.39
To find interest we use formula A=P+I'
since A= 14794.39 and P=5000
we have: A=P+I 14794.39=5000+I
I= 14794.39 -5000
I=9794.39
The answer is (-8, 16)
a scale factor of 2 will enlarge the image. all you need to do is multiply the x and y by 2.
Answer:
a) x = 1225.68
b) x = 1081.76
c) 1109.28 < x < 1198.72
Step-by-step explanation:
Given:
- Th random variable X for steer weight follows a normal distribution:
X~ N( 1154 , 86 )
Find:
a) the highest 10% of the weights?
b) the lowest 20% of the weights?
c) the middle 40% of the weights?
Solution:
a)
We will compute the corresponding Z-value for highest cut off 10%:
Z @ 0.10 = 1.28
Z = (x-u) / sd
Where,
u: Mean of the distribution.
s.d: Standard deviation of the distribution.
1.28 = (x - 1154) / 86
x = 1.28*86 + 1154
x = 1225.68
b)
We will compute the corresponding Z-value for lowest cut off 20%:
-Z @ 0.20 = -0.84
Z = (x-u) / sd
-0.84 = (x - 1154) / 86
x = -0.84*86 + 1154
x = 1081.76
c)
We will compute the corresponding Z-value for middle cut off 40%:
Z @ 0.3 = -0.52
Z @ 0.7 = 0.52
[email protected] < x < [email protected]
-.52*86 + 1154 < x < 0.52*86 + 1154
1109.28 < x < 1198.72
If you were to draw the cosx and sinx graph there will be infinite solutions at their interceptions which are the multiple of pi/4
