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3 years ago

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For the function: f(x) = 21 + 2x − 5x2 Find f(3)

1 answer:

allochka39001 [22]3 years ago

6 0

F(3)=-18

You just replace x for three for your equation and then use Ofer of operations to solve it.

So f(3)= 21+ 2(3)-5(3)^2

The exponent goes first: f(3)= 21+ 2(3)-5(9)

Next is multiplication: f(3)= 21+ 6-45

Now add: f(3)= 27-45

Finally subtract: f(3)= -18

Hope this helps!

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evablogger [386]

Answer:

Solution of equation ( q ) = <u>1</u><u>6</u>

Step-by-step explanation:

In this question we have given an equation that is <u>3 </u><u>(</u><u> </u><u>q </u><u>-</u><u> </u><u>7</u><u> </u><u>)</u><u> </u><u>=</u><u> </u><u>2</u><u>7</u><u> </u>and we have asked to solve this equation that means to find the value of <u> </u><u>q</u><u> </u><u>.</u>

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$\quad \: \longmapsto \: 3(q - 7) = 27$

<u>Step </u><u>1</u><u> </u><u>:</u> Solving parenthesis :

$\quad \: \longmapsto \:3q - 21 = 27$

<u>Step </u><u>2</u><u> </u><u>:</u> Adding 21 on both sides :

$\quad \: \longmapsto \:3q - \cancel{ 21} + \cancel{21} = 27 + 21$

On further calculations we get :

$\quad \: \longmapsto \:3q = 48$

<u>Step </u><u>3 </u><u>:</u> Dividing by 3 from both sides :

$\quad \: \longmapsto \: \frac{ \cancel{3}q}{ \cancel{3}} = \cancel {\frac{48}{3} }$

On further calculations we get :

$\quad \: \longmapsto \: \pink{\boxed{\frak{q = 16}}}$

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<u>Verifying</u><u> </u><u>:</u><u> </u><u>-</u>

Now we are very our answer by substituting value of q in the given equation . So ,

3 ( q - 7 ) = 27

3 ( 16 - 7 ) = 27

3 ( 9 ) = 27

27 = 27

L.H.S = R.H.S

Hence, Verified.

<u>Therefore</u><u>,</u><u> </u><u>our </u><u>solution</u><u> </u><u>is </u><u>correct</u><u> </u><u>.</u>

<h2><u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>

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3 years ago

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Answer:

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