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Fudgin [204]
4 years ago
7

The probability that a flight departs on time is 0.83; the probability that it arrives on time is 0.82; and the probability that

it departs and arrives on time is 0.78. find the probability that a plane arrives on time given that it departs on time, computed to the nearest two decimal points.
Mathematics
1 answer:
Lunna [17]4 years ago
6 0

Solution: Let P(A) denotes the probability that the plane arrives on time and let P(D) denotes the probability that the plane departs on time. Therefore, we have:

P(A) = 0.82, P(D)=0.83, P(A \cap D)=0.78

Now the probability that a plane arrives on time given that it departs on time is:

P(A|D) = \frac{P(A \cap D)}{P(D)}

                  =\frac{0.78}{0.83} =0.94

Therefore, the probability that a plane arrives on time given that it departs on time = 0.94

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