What is 5/16 x 246/1000

Question 27 of 28 1 Point What is the slope of the line shown below? (3,-2) (2,-4)

Gwar [14]

Answer:

The slope is 2

Step-by-step explanation:

To find the slope given two points, we use the formula

m = (y2-y1)/(x2-x1)

= (-4--2)/(2-3)

= (-4+2)/(2-3)

= -2/-1

= 2

6 0

3 years ago

Please help i really need this

lorasvet [3.4K]

Answer:

ok put me brainliest please

its 215$

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Which is greater ? 9/20 or 0.06

bekas [8.4K]

9/20 is greater

9/20 = 0.45
..............

4 0

3 years ago

Read 2 more answers

The question is in the picture. Plz helppp it is due tonight

Mkey [24]

Answer:

Step-by-step explanation:

We're given one equation, we have to find the other equation and solve each for 200, and whichever has the lower x is the winner

for Jayden we are given

$(0, 48), (1, 56), (2, 64), (3, 72), (4, 80)$

This looks to be a line. The y values are each separated by a common difference

We can use two points to describe the line

$m = \frac{y_2-y_1}{x_2-x_1} = \frac{80-48}{4-0} = \frac{32}{4} = 8\\ K = 8m + b\\48 = 8(0) + b\\b = 48\\so\\K = 8m + 48$

Now we can set both $K = 8m + 48$ and $K = m^2 + 10$ equal to 200

$200 = 8m + 48\\152 = 8m \\m = \frac{152}{8} = 19$

$200 = m^2 + 10\\m^2 = 190\\m = \sqrt{190} = 13.784$

Keiko's blog will reach 200 subscribers fastest.

7 0

3 years ago

I am having trouble with this relative minimum of this equation.

Norma-Jean [14]

Answer:

So the approximate relative minimum is (0.4,-58.5).

Step-by-step explanation:

Ok this is a calculus approach. You have to let me know if you want this done another way.

Here are some rules I'm going to use:

$(f+g)'=f'+g'$ (Sum rule)

$(cf)'=c(f)'$ (Constant multiple rule)

$(x^n)'=nx^{n-1}$ (Power rule)

$(c)'=0$ (Constant rule)

$(x)'=1$ (Slope of y=x is 1)

$y=4x^3+13x^2-12x-56$

$y'=(4x^3+13x^2-12x-56)'$

$y'=(4x^3)'+(13x^2)'-(12x)'-(56)'$

$y'=4(x^3)'+13(x^2)'-12(x)'-0$

$y'=4(3x^2)+13(2x^1)-12(1)$

$y'=12x^2+26x-12$

Now we set y' equal to 0 and solve for the critical numbers.

$12x^2+26x-12=0$

Divide both sides by 2:

$6x^2+13x-6=0$

Compaer $6x^2+13x-6=0$ to $ax^2+bx+c=0$ to determine the values for $a=6,b=13,c=-6$ .

$a=6$

$b=13$

$c=-6$

We are going to use the quadratic formula to solve for our critical numbers, x.

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-13 \pm \sqrt{13^2-4(6)(-6)}}{2(6)}$

$x=\frac{-13 \pm \sqrt{169+144}}{12}$

$x=\frac{-13 \pm \sqrt{313}}{12}$

Let's separate the choices:

$x=\frac{-13+\sqrt{313}}{12} \text{ or } \frac{-13-\sqrt{313}}{12}$

Let's approximate both of these:

$x=0.3909838 \text{ or } -2.5576505$ .

This is a cubic function with leading coefficient 4 and 4 is positive so we know the left and right behavior of the function. The left hand side goes to negative infinity while the right hand side goes to positive infinity. So the maximum is going to occur at the earlier x while the minimum will occur at the later x.

The relative maximum is at approximately -2.5576505.

So the relative minimum is at approximate 0.3909838.

We could also verify this with more calculus of course.

Let's find the second derivative.

$f(x)=4x^3+13x^2-12x-56$