Answer: 0.8461
Step-by-step explanation:
Given : 
Let x be the random variable that represents the cost for the hospital emergency room visit.
We assume that cost for the hospital emergency room visit is normally distributed .
z-score for x=1000 ,
![z=\dfrac{1000-1400}{392}\approx-1.02\ \ \ [\because z=\dfrac{x-\mu}{\sigma}]](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B1000-1400%7D%7B392%7D%5Capprox-1.02%5C%20%5C%20%5C%20%5B%5Cbecause%20z%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5D)
Using z-value table , we have
P-value =P(x>1000)=P(z>-1.02)=1-P(z≤ -1.02)=1-0.1538642
=0.8461358≈0.8461 [Rounded nearest 4 decimal places]
Hence, the probability that the cost will be more than $1000 = 0.8461
3(12)/10(12) + 7(10)/12(10) = 36/120 + 70/120
==> 18/60 + 35/60 = 53/60
i think the answer is linear I am not sure though
<span>(-45 + (-12) / 2 = -28.5
</span>So the answer is -28.5
Answer:
8/3ft
Step-by-step explanation:
To find how high she would bounce, we need to first understand that her height of each jump would be multiplied by 2/3 given that each bounce afterwards is two thirds as high as the bounce before.
We can then set the equation:
6 x 2/3 x 2/3
=6 x (2/3)^2
=8/3
Therefore the answer is 8/3 ft.
Hope it helps!
