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Oxana [17]
3 years ago
13

49x^2 -_x + 16 Can someone help with the missing number

Mathematics
2 answers:
belka [17]3 years ago
8 0

Answer:

Step-by-step explanation:

4x² + 28x + 49

4x² + 14x + 14x + 49

2x(2x) + 2x(7) + 7(2x) + 7(7)

2x(2x + 7) + 7(2x + 7)

(2x + 7)(2x + 7)

(2x + 7)²

= 28

mihalych1998 [28]3 years ago
5 0

Step-by-step explanation:

I'm guessing this is competing the perfect square

so it's 56

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10%

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Estimate 2.8 divided by 6
marin [14]

\huge\fcolorbox{blue}{Red}{Solution→}

  • 2.8 ÷ 6 = 0.4666666.... it will continue
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2(b+3c) equivalent expressions<br>Options: <br><br>3(b+2c)<br>(b+3c) +(b+3c)<br>None of the above
Lana71 [14]
2(b + 3c) → We first need to simplify this.

Simplify.

2b + 6c

1st Option : 

3(b + 2c)

Simplify.

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2nd Option :

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Simplify.

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5 0
3 years ago
One week the music store sold 2 trumpets, 3 clarinets, and 5 violins for $1,240. The next week, they sold 3 trumpets, 1 clarinet
garik1379 [7]

Answer:

Cost of Trumpets: $174

Cost of Clarinets: $149

Cost of Violins: $89

Step-by-step explanation:

Got it correct

4 0
3 years ago
Select the quadrant in which the terminal side of the angle falls.
Sedbober [7]

Answer:

The answer is below

Step-by-step explanation:

Select the quadrant in which the terminal side of the angle falls.

210° terminates in quadrant

-150° terminates in quadrant

390° terminates in quadrant

Solution:

The x and y axis divides the cartesian plane into four equal parts known as the four quadrants.

Angles between 0° and 90° are in the first quadrant, angles between 90° and 180° are in the second quadrant, angles between 180° and 270° are in the third quadrant while angles between 270° and 360° are in the fourth quadrant.

a) Since 210 degrees is between 180° and 270°, hence it terminates in the third quadrant.

b) -150° = 360 - 150 = 210°. Since 210 degrees is between 180° and 270°, hence it terminates in the third quadrant.

c) 390° = 390° - 360° = 30°.

Since 30 degrees is between 0° and 90°, hence it terminates in the first quadrant.

 

8 0
3 years ago
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