Answer:
Relative frequencies
First row
0.8125 ,0.1875 ,16
Second row
0.555 ,0.444 ,9
third row
18 , 7 , 25
Step-by-step explanation:
Given data
allowance No allowance total
Chores 13 3 16
<u>No chores 5 4 9</u>
<u>Total 18 7 25</u>
<u><em>Relative frequencies</em></u>
allowance No allowance total
Chores
16
No chores
9
Total <u> 18 7 25</u>
Answer:
Number of Pennies = 30
Number of Dimes = 90
Step-by-step explanation:
Let the number of pennies be p and number of dimes be d
We can write 2 equations and use substitution method to solve.
<u>Total value of all the coins is 9.30:</u>
We can write:
0.01p + 0.1d = 9.30
Note: value of penny is 0.01 and dime is 0.1, in dollars
<u>Number of dimes is 3 times number of pennies:</u>
We can write:
d = 3p
Now putting 2nd equation in first and solving for p:
0.01p + 0.1(3p) = 9.30
0.01p + 0.3p = 9.30
0.31 p = 9.30
p = 9.30 /0.31
p = 30
Now we know d = 3p, so d = 3 (30) = 90
Hence
Number of Pennies = 30
Number of Dimes = 90
On the account with interest compounded annually, the account balance will be
P*(1 +r)^t
4500*1.06³ = 5358.57
so the interest earned will be
5358.57 -4500 = 859.57
On the account with simple interest, the interest earned will be
I = Prt
I = 4500*.06*3
I = 810.00
The total interest earned on the two accounts will be
$859.57 +810.00 = $1669.57 . . . . . . . . selection A
Answer:
Check the explanation
Step-by-step explanation:
Here we have to first of all carry out dependent sample t test. consequently wore goggles first was selected at random for the reason that the reaction time in an emergency taken with goggles would be greater than the amount of reaction time in an emergency taken with not so weakened vision. So that we will get the positive differences d = impaired - normal
b)
To find 95% confidence interval first we need to find sample mean and sample sd for difference d = impaired minus normal.
We can find it using excel that is in the first attached image below,
Therefore sample mean
= 0.98
Sample sd
= 0.3788
To find 95% Confidence interval we can use TI-84 calculator,
Press STAT ----> Scroll to TESTS ---- > Scroll down to 8: T Interval and hit enter.
Kindly check the attached image below.
Therefore we are 95% confident that mean difference in braking time with impaired vision and normal vision is between ( 0.6888 , 1.2712)
Conclusion : As both values in the interval are greater than 0 , mean difference impaired minus normal is not equal to 0
There is significant evidence that there is a difference in braking time with impaired vision and normal vision at 95% confidence level .
Answer:
-4x-y=24= - 4 · (-7) - 4 = 24