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Ganezh [65]
3 years ago
12

Barbara has $70.00 in her pocket and a $20 gift card. which purchase will she be able to make without having to use her credit c

ard?
Mathematics
2 answers:
Tresset [83]3 years ago
4 0

Answer:

Step-by-step explanation:

six puzzles for $11.99 each and a board game for $15.89

Kipish [7]3 years ago
3 0
If Barbara has $ 70.00 in her pocket and a $ 20 gift card. then the maximumm amount she can pruchase is $ 70 + $ 20 = $ 90
so let x be purchase will she be able to make without having to use her credit card
x >= $ 90
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alexandr402 [8]
It should be 54 because height times width
6 0
3 years ago
If g(x) =x^2 + 1, find g(4)
Papessa [141]

Answer:

17

Step-by-step explanation:

Since we are evaluating <em>g(x)</em> for g(4), we would substitute <em>x</em> in the equation with 4.

<em>x</em>² + 1

(4)²+ 1

16 + 1

17

I hope this helps

4 0
3 years ago
Help me please I need help​
adoni [48]
R=17/3 alternative form would be r= 5 2/3, r=5.6 those would all be the answers depending on what form you need
8 0
3 years ago
Read 2 more answers
A large emerald with a mass of 378.24 grams was recently discovered in a mine. If the density of the emerald is 2.76grams over c
bogdanovich [222]

Answer:

Volume of emerald = 137.04cm³

Step-by-step explanation:

Given that:

Mass of emerald = 378.24grams

Density of emerald = 2.76grams/cm³

Volume = ?

The equation for this relationship is ρ = m / V in which ρ is density, m is mass (kg or g) and V is volume (cm³ or m³) making the density unit kg/m³ or g/cm³.

Therefore

Density = mass/volume

Volume = Mass/density

i.e

Volume of emerald = Mass of emerald / Density of emerald

Volume of emerald = 378.24grams / 2.76grams/cm³

Volume of emerald = 137.043cm³ ~137.04cm³

Volume of emerald =137.04cm³

6 0
3 years ago
Which of the following is an example of the additive identity?<br> a +(-a) = 0<br> a+0=0<br> a+0= a
UNO [17]

Answer:

a+0= a

Step-by-step explanation:

we know that

The <u>additive identity</u> property says that if you add a real number to zero or add zero to a real number, then you get the same real number back

so

Let

a -----> a real number

a+0=0+a=a

therefore

a+0= a

4 0
3 years ago
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