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puteri [66]
3 years ago
13

What is 2x^3•4y^2 simplified

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
4 0
(2x)^3*(4y)^2
=8x^3*16y^2
=128x^3y^2
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Question 2
Slav-nsk [51]

Answer:

wanna help, but please specify what the (2) means.

our take a picture of the problem and makes me post.

4 0
2 years ago
Find the equation of the line parallel to y=2x+1 that contains point (14,3)
Sophie [7]

First of all, remember what the equation of a line is:

y=mx+b

Where: 

m=slope

b=y-intercept.

Given this information, we can start by plugging in what we know, we are given the slope which is 2 so we can fill that in, remember m=slope

y=2x+b

To find b, think about what your (x,y) point means:<span>(14,3). When x of the line is 14, y of the line must be 3.

Because we were given the point (14,3) 
</span>

We need to find the value of b.  The 2 is already set and x and y are variables. We want the equation for the line that specifically passes through the given point (14,3).

<span>Plug in for x the number 14 and for y the number 3:
</span>(14,3).
 y=mx+b or 3=2 × 14+b,

solving for b: b=3-(2)(14). b=-25.

<span>Plug that in for b: 
</span><span>y=2x-25
<span>Final answer: 
</span><span>y=2x-25</span></span><span><span>
</span></span>
8 0
2 years ago
Please help me solve this problem -5= -32 please and thank you
Ymorist [56]

Answer: false

Step-by-step explanation:  Compare -5 and -32. They do not equal each other.

8 0
2 years ago
The mean amount of money spent on lunch per week for a sample of 458458 college students is $43$ 43. If the margin of error for
a_sh-v [17]

Answer:

The 99% confidence interval for the mean amount of money spent on lunch per week for all college students is between $41.40 and $44.60.

Step-by-step explanation:

A confidence interval has two bounds, a lower bounds and an upper bound.

These bounds depend on the sample mean and the margin of error.

The lower bound is the sample mean subtracted by the margin of error.

The upper bound is the margin of error added to the sample mean.

In this problem, we have that:

The sample mean is $43.

The margin of error is $1.60 for a 99% confidence interval.

Lower bound: 43 - 1.60 = $41.40

Upper bound: 43 + 1.60 = $44.60

The 99% confidence interval for the mean amount of money spent on lunch per week for all college students is between $41.40 and $44.60.

6 0
3 years ago
0.5t+0.25(t+16)=4+0.75<br><br> help please!!
Zigmanuir [339]
X is equal to the number 1
6 0
3 years ago
Read 2 more answers
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