Question

Use the graph below to answer the question that follows:

Answer 1

For this case the amplitude is given by:
 A = (l-1l + 3) / 2
 A = 4/2
 A = 2
 The middle line is given by:
 y = 1
 The period of the function is given by:
 T = l x2 - x1 l
 T = l 0 - 2pi l
 T = l - 2pi l
 T = 2pi
 Answer:
 Amplitude: 2; period: 2π; midline: y = 1