The complete question in the attached figure
we know that
the diagonals of a rhombus intersect to form right angles,
so
angle ACE is ----------> (90°-64°)-----------> 26°
ACE is the angle bisector of ACD, this means that ACD is ---------> 26 x 2 = 52°
The diagonals are angle bisectors to the opposite corners
so
ACD = ACB = 52°
and
BCD = 52 x 2 = 104°
For a rhombus, opposite angles are equivalent,
so
BAD = BCD = 104°
the answer is
angle BAD=104°
D) square the number and add 2
Answer:
A. csc θ=1/sinθ
Step-by-step explanation:
From SOHCAHTOA,
sine = opposite/ hypotenuse
Cos = adjacent / hypotenuse
Tan = opposite / adjacent
In a right angled triangle, the cosecant of an angle is the length of the hypotenuse divided by the length of the side opposite the angle. This is the inverse of sine , therefore:
Csc Ф = 1/ sinФ
Answer:
1) 0.700
2) 0.730
3) 0.030
4) 0.959
Step-by-step explanation:
1) proportion of support for the ban with at least one child =
= 
= 0.700
2) proportion of support for the ban with no child =
= 
= 
= 0.730
3) Difference in proportion of supporters for the ban between those with atleast one child and those with no child
= 0.700 - 0.730
= -0.03
4) Relative risk = 
=
= 0.959
6:3 boys to girls.
say for the sake of it, there are 60 boys and 30 girls.that makes 90 children.if 1/2 of the boys wore hats, then 30 boys wore hatsif 1/3 of the girls wore hats, then 10 girls wore hatsif 30 boys and 10 girls wore hats, then 40 children wore hatsif 40 children wore hats, then 40/90 children wore hats40/90 can be simplified to 4/94/9 children wore hats