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allochka39001 [22]
3 years ago
6

Can someone please tell me what the growth rate is. Thanks in advance.

Mathematics
1 answer:
aalyn [17]3 years ago
5 0

Answer:

44 years per year

18 males

34 female

and total 44

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Find the total number of outcomes, rolling a number cube and tossing<br> two coins
Tcecarenko [31]

A number cube has 6 different numbers.

A coin can have 2 outcomes ( heads or tails.)

Total out comes = 6 x 2 x 2 = 24

5 0
2 years ago
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
. Tickets to a football game cost a dollars for adults and s dollars for students. If a family of 2 adults and 3 students buy ti
garri49 [273]

Answer:

Choice C is the answer.

Known information:

a = adult $

s = student $

We have 2 adults and 3 students.

Step-by-step explanation:

To find the total price of tickets given a # of students and adults, multiply a by the # of adults and multiply s by the # of students. Therefore, it would look like this:

2a + 3s = price

Therefore, choice C is the answer.

Hope this helps!

3 0
2 years ago
In trip 1 you drove 104 miles in 4 gallons; in trip 2 you drove 78 miles how many gallons did you use in trip 2
BlackZzzverrR [31]
First do 104/4 which equals which equals 26
so you can drive 26miles on one gallon

then do 78/26 which equals 3

so you used 3 gallons of gas on trip 2
4 0
3 years ago
Read 2 more answers
What is the solution to the equation?
Otrada [13]

Answer:

The format of this equation is wrong

3 0
3 years ago
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