<img src="https://tex.z-dn.net/?f=%7Cx-%5Cfrac%7B1%7D%7B2%7D%7C%3D3%5Cfrac%7B2%7D%7B3%7D" id="TexFormula1" title="|x-\frac{1}{2}

All categories

3 years ago

|=3\frac{2}{3}" alt="|x-\frac{1}{2}|=3\frac{2}{3}" align="absmiddle" class="latex-formula">
Please answer with explanation. If correct, I will mark brainliest!

Mathematics

2 answers:

Bogdan [553]3 years ago

8 0

Answer:

x= 4 1/6, -3 1/6

Step-by-step explanation:

Hope this helps

Delicious77 [7]3 years ago

6 0

The answer is X=5/2 and -3/2

You might be interested in

(b) The sum of a number and its reciprocal is<br> 2 1/6.Find the number

Phoenix [80]

Answer:

Step-by-step explanation:

n+1/2n=7/2

2n^2+1/2=7/2

4n^2+2=14

4n^2=12

n^2=3

n=radical3

4 0

2 years ago

Suppose the expected tensile strength of type-A steel is 103 ksi and the standard deviation of tensile strength is 7 ksi. For ty

ExtremeBDS [4]

Answer:

i So the approximate distribution of $\= X$ is $\mu_{\= X} =103$ and $\sigma_{\= X} = 0.783$

ii So the approximate distribution of $\= Y$ is $\mu_{\= Y} =105$ and $\sigma_{\= Y} = 0.645$

the approximate distribution of $\=X - \= Y$ is $E (\= X - \= Y) = -2$ and $\sigma_{\= X - \=Y}=1.029$

Here we can see that the mean of the approximate distribution is negative which tell us that this negative value of the data for $\=X - \= Y$ sample are more and their frequency occurrence is higher than the positive values

the value of $P(-1 \le \=X - \= Y \le 1)$ is $= -0.1639$

Step-by-step explanation:

From the question we are given that

The expected tensile strength of the type A steel is $\mu_A = 103 ksi$

The standard deviation of type A steel is $\sigma_A = 7ksi$

The expected tensile strength of the type B steel is $\mu_B = 105\ ksi$

The standard deviation of type B steel is $\sigma_B = 5 \ ksi$

Also the assumptions are

Let $\= X$ be the sample average tensile strength of a random sample of 80 type-A specimens

Here $n_a =80$

Let $\= Y$ be the sample average tensile strength of a random sample of 60 type-B specimens.

Here $n_b = 60$

Let the sampling distribution of the mean be

$\mu _ {\= X} = \mu$

$=103$

Let the sampling distribution of the standard deviation be

$\sigma _{\= X} = \frac{\sigma }{\sqrt{n_a} }$

$= \frac{7}{\sqrt{80} }$

$=0.783$

So What this mean is that the approximate distribution of $\= X$ is $\mu_{\= X} =103$ and $\sigma_{\= X} = 0.783$

For $\= Y$

The sampling distribution of the sample mean is

$\mu_{\= Y} = \mu$

$= 105$

The sampling distribution of the standard deviation is

$\sigma _{\= Y} = \frac{\sigma }{\sqrt{n_b} }$

$= \frac{5}{\sqrt{60} }$

$= 0.645$

So What this mean is that the approximate distribution of $\= Y$ is $\mu_{\= Y} =105$ and $\sigma_{\= Y} = 0.645$

Now to obtain the approximate distribution for $\=X - \= Y$

$E (\= X - \= Y) = E (\= X) - E(\= Y)$

$= \mu_{\= X} - \mu_{\= Y}$

$= 103 -105$

$= -2$

The standard deviation of $\=X - \= Y$ is

$\sigma_{\= X - \=Y} = \sqrt{\sigma_{\= X}^2 - \sigma_{\= Y}^2}$

$= \sqrt{(0.783)^2 + (0.645)^2}$

$=1.029$

Now to find the value of $P(-1 \le \=X - \= Y \le 1)$

Let us assume that $F = \= X - \= Y$

$P(-1 \le F \le 1)$ $= P [\frac{-1 -E (F)}{\sigma_F} \le Z \le \frac{1-E(F)}{\sigma_F} ]$

$= P[\frac{-1-(-2)}{1.029} \le Z \le \frac{1-(-2)}{1.029} ]$

$= P[0.972 \le Z \le 2.95]$

$= P(Z \le 0.972) - P(Z \le 2.95)$

Using the z-table to obtain their z-score

$= 0.8345 - 0.9984$

$= -0.1639$

3 0

3 years ago

The monthly cost of driving a car depends on the number of miles driven. Lynn found that in May her driving cost was $380 for 48

andrezito [222]

Answer:

$y=0.2x+284$

Step-by-step explanation:

Let x be the distance driven, d-distance and C our constant.

Our information can be presented as:

$y=mx+c\\\\450=830x+C\ \ \ \ \ \ \ \ \ eqtn 1\\\\380=480x+C\ \ \ \ \ \ \ \ \ eqtn 2$

#Subtracting equation 2 from 1:

$70=350x\\x=0.2$

Hence the fixed cost per mile driven, $x$ is $0.20

To find the constant, $C$ we substitute $x$ in any of the equations:

$450=830x+C\ \ \ \ \ \ \ X=0.2\\\therefore C=450-830\times0.2\\=284$

Now, substituting our values in the linear equation:

$y=0.2x+284$ #y=cost of driving, x=distance driven

Hence the linear equation for the cost of driving is y+0.2x+284

7 0

3 years ago

Question in screenshot

sesenic [268]

Answer:

Step-by-step explanation:

use pythagorean theorm

√(8^2+6^2) = 10

6 0

3 years ago

Shannon pours 4 different liquid ingredients into a bowl. The sum of the liquid ingredients is 8.53 liters. Two of her measureme

saveliy_v [14]

All you have to do is multiply those two numbers and whatever u get is ur answer

4 0

3 years ago