Let A = {0,1,2,3,4,5}<br>B = {2,4,6,8}<br>C= {1,3,5,7}<br>Verity (AUB) UC=AU (BUC) <br>
Angelina_Jolie [31]
<em><u>Hope</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>help</u></em><em><u> </u></em><em><u>u</u></em><em><u>.</u></em>
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Answer:
596.34m approx
Step-by-step explanation:
Given data
Let the Starting point be x
A helicopter flew north 325 meters from x
Then flew east 500 meters
Let us apply the Pythagoras theorem to solve for the resultant which is the distance from the starting position
x^2= 325^2+500^2
x^2=105625+250000
x^2= 355625
x= √355625
x=596.34m
Hence the distance from the starting point is 596.34m approx
Answer:
x+2
Step-by-step explanation:
if a to the power of b is equal to x then a to the power of b +2 is x+2
Your answer should be y=8x2
