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3 years ago

Which coordinate pair is a solution to the following system? A- (0.20) B-(1,-3) C(5,5) D-(13,20

Mathematics

1 answer:

kirza4 [7]3 years ago

4 0

Answer:

x=5/2, y=0 & x=5, y=5. So the answer is C).

Step-by-step explanation:

2x^2-13x+20=2x-5

2x^2-13x-2x+20-(-5)=0

2x^2-15x+20+5=0

2x^2-15x+25=0

factor out the trinomial

(2x-5)(x-5)=0

zero property

2x-5=0, x-5=0

2x=0+5=5, 2x=5, x=5/2

x=0+5=5

y=2(5/2)-5=5-5=0

y=2(5)-5=10-5=5

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Y=x(2)-2x-3 find the value of x when y=1

Volgvan

1 = x(2) - 2x - 3
1 = 2x + -2x + - 3
1 = (2x + -2x) + (-3)
1 = -3
1 - 1 = -3 -1
0 = -4

No solutions

4 0

3 years ago

Which is an asymptofe of the graph the function y=cot(x-2π/3)

Shalnov [3]

Hello.

C) x=4π/3

The variable x in the cotangent argument has a unit coefficient, so the period is π, just as it is in the parent function cot(x).

Can you graph y = cot(x)? By subtracting the constant π/6 from the argument, that graph is translated to the right by π/6. Just as with cot(x), it is decreasing everywhere.

Have a nice day

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4 years ago

In order to estimate the average time spent on the computer terminals per student at a local university, data were collected fro

Ksju [112]

Answer:

d. 0.133

Step-by-step explanation:

-Standard error is calculated using the formula:

$E=\frac{\sigma}{\sqrt{n}}\\\\\sigma-=standard \ deviation\\n=sample \ size$

#We substitute the given values in the formula to solve for E:

$E=\frac{\sigma}{\sqrt{n}}\\\\=\frac{1.2}{\sqrt{81}}\\\\=0.133$

Hence, the standard error is 0.133 and the correct option is d

7 0

3 years ago

Andres boards a Ferris wheel at the 3-o'clock position and rides the Ferris wheel for multiple revolutions. The Ferris wheel rot

Gelneren [198K]

Answer:

a) r(t) = 0.783t radians

b) h(t) = 30cos(0.783*t) feet

Step-by-step explanation:

The situation is depicted in the picture attached

<h3>(see picture) </h3>

Since the angular speed is constant, to find an expression for the angle r(t) in radians we just cross-multiply using the fact that 1 min = 60 seconds

4.7 radians __________ 60 seconds

r(t) radians ____________ t seconds

$\large \displaystyle\frac{4.7}{r(t)}=\displaystyle\frac{60}{t}\Rightarrow r(t)=(4.7/60)t \Rightarrow\\\\\boxed{r(t)=0.783t\;rad}$