Answer:
<em>y=</em><em>1</em><em>/</em><em>3</em><em> </em><em>would </em><em>be </em><em>the </em><em>correct</em><em> </em><em>answer</em><em> </em><em>as </em><em>long </em><em>as </em><em>the </em><em>x </em><em>is </em><em>not </em><em>only </em><em>attached</em><em> to</em><em> the</em><em> </em><em>three,</em><em> </em><em>but </em><em>1</em><em>/</em><em>3</em><em> </em><em>as </em><em>a </em><em>whole</em><em>.</em><em> </em><em>I </em><em>hope</em><em> </em><em>this </em><em>helps!</em>
Answer:
n < 20
Step-by-step explanation:
2n – 1 < 39
Add 1 to each side
2n – 1+1 < 39+1
2n < 40
Divide each side by 2
2n/2 < 40/2
n < 20
184.19 cm²
IF I WAS CORRECT PLEASE THANK ME. =)
THIS IS AN EXAMPLE:
Answer: Bradley scored 854 points and Harner scored 748 points.
Step-by-step explanation:
Start by representing the problem mathematically. "B" will represent Bradley's score, and "H" will represent Harner's score.
B+H=1602 represents that the sum of the scores is 1602.
B-H=106 represents that Bradley has 106 more points than Harner.
Now, combine the like terms in the two equations to get 2B=1708 . Now divide each side by two to find that Bradley scored 854 points.
Now, we can just subtract Bradley's score from the total score to get Harner's score. 1602-854=748, so Harner scored 748 points.