Answer:
29
Explanation:
Let John be x years old.
Michael is <span>x+17</span> years old.
In four years time, the sum of their ages will be 49:
<span>x+x+17+2<span>(4)</span>=49</span>
<span>2x=24</span>
<span>x=12</span>
So Michael is <span>12+17=29</span> years old now.
To find the mean of something, add all the numbers then divide by the number of numbers there are.
40,000 + 50,000 + 40,000 + 60,000 + 90,000 = 280,000
Then divide:
280,000/5 = 56,000
The mean of the annual salaries at the company is 56,000
Hope this helped! If you have anymore questions or don't understand, please comment or DM me. :)
This is a little long, but it gets you there.
- ΔEBH ≅ ΔEBC . . . . HA theorem
- EH ≅ EC . . . . . . . . . CPCTC
- ∠ECH ≅ ∠EHC . . . base angles of isosceles ΔEHC
- ΔAHE ~ ΔDGB ~ ΔACB . . . . AA similarity
- ∠AEH ≅ ∠ABC . . . corresponding angles of similar triangle
- ∠AEH = ∠ECH + ∠EHC = 2∠ECH . . . external angle is equal to the sum of opposite internal angles (of ΔECH)
- ΔDAC ≅ ΔDAG . . . HA theorem
- DC ≅ DG . . . . . . . . . CPCTC
- ∠DCG ≅ ∠DGC . . . base angles of isosceles ΔDGC
- ∠BDG ≅ ∠BAC . . . .corresponding angles of similar triangles
- ∠BDG = ∠DCG + ∠DGC = 2∠DCG . . . external angle is equal to the sum of opposite internal angles (of ΔDCG)
- ∠BAC + ∠ACB + ∠ABC = 180° . . . . sum of angles of a triangle
- (∠BAC)/2 + (∠ACB)/2 + (∠ABC)/2 = 90° . . . . division property of equality (divide equation of 12 by 2)
- ∠DCG + 45° + ∠ECH = 90° . . . . substitute (∠BAC)/2 = (∠BDG)/2 = ∠DCG (from 10 and 11); substitute (∠ABC)/2 = (∠AEH)/2 = ∠ECH (from 5 and 6)
- This equation represents the sum of angles at point C: ∠DCG + ∠HCG + ∠ECH = 90°, ∴ ∠HCG = 45° . . . . subtraction property of equality, transitive property of equality. (Subtract ∠DCG+∠ECH from both equations (14 and 15).)
Answer:
C: 28 inches
Step-by-step explanation:
Perimeter is when you add the length of each sides together.
Y=money spent
X=games played
For the winter festival, it would be y=2x+20
For the fall festival, it would be y=5x+5
