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tigry1 [53]
3 years ago
8

The sum of four consecutive odd integers is -72. Write an equation to model this situation, and ind the values of the four integ

ers.
Mathematics
1 answer:
Nutka1998 [239]3 years ago
3 0

Answer:

  • equation: (x-3) +(x-1) +(x+1) +(x+3) = -72
  • values: -21, -19, -17, -15

Step-by-step explanation:

When dealing with consecutive integers, it often simplifies the problem to work with their average value. We know the average value of the integers in this problem is the even integer between the middle two. We can call it x, and write the equation ...

  (x-3) +(x-1) +(x+1) +(x+3) = -72

This simplifies to ...

  4x = -72 . . . . . . . we knew this before we wrote the above equation, since the sum of 4 numbers is 4 times their average.

  x = -18 . . . . . . . . the middle number of the sequence

So, the numbers are:

  • -18-3 = -21
  • -18-1 = -19
  • -18+1 = -17
  • -18+3 = -15

_____

A more conventional approach is to define the variable as the integer at one end or the other of the sequence. If we make it be the lowest number, then the equation is ...

  (x) +(x +2) +(x +4) +(x +6) = -72

and that simplifies to ...

  4x +12 = -72 . . . . . collect terms

  4x = -84 . . . . . . . . subtract 12

  x = -21 . . . . . . . . . . divide by 4

Now, the other three numbers are found by adding 2, 4, and 6 to this one.

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Haroldo, Xerxes, Regina, Shaindel, Murray, Norah, Stav, Zeke, Cam, and Georgia are invited to a dinner party. They arrive in a r
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Answer: The probability is P = 0.056

Step-by-step explanation:

The invited ones are:

Haroldo, Xerxes, Regina, Shaindel, Murray, Norah, Stav, Zeke, Cam, and Georgia

So we have a total of 10 persons.

The case where Xerxes arrives first and Regina arrives last is:

We have 10 slots, each slot corresponds to who arrived in which time.

For the first slot we have only one option, this is Xeres.

For the next slot we have 8 options (because Xeres already arrived, and Regina must arrive at last)

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So the combinations are:

C = 1*8*7*6*5*4*3*2*1*1 = 40320

Now, the total number of combinations is:

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Factorise 9w² - 100<br><br><br>​
ohaa [14]

Answer:

9\, w^{2} - 100 = (3\, w - 10) \, (3\, w + 10).

Step-by-step explanation:

Fact:

\begin{aligned} & (a - b)\, (a + b)\\ =\; & a^{2} + a\, b - a\, b - b^{2} \\ =\; & a^{2} - b^{2} \end{aligned}.

In other words, (a^{2} - b^{2}), the difference of two squares in the form a^{2} and b^{2}, could be factorized into (a - b)\, (a + b).

In this question, the expression (9\, w^{2} - 100) is the difference between two terms: 9\, w^{2} and 100.

  • 9\, w^{2} is the square of 3\, w. That is: (3\, w)^{2} = 9\, w^{2}.
  • On the other hand, 10^{2} = 100.

Hence:

9\, w^{2} - 100 = (3\, w)^{2} - (10)^{2}.

Apply the fact that a^{2} - b^{2} = (a - b) \, (a + b) to factorize this expression. (In this case, a = 3\, w whereas b = 10.)

\begin{aligned}& 9\, w^{2} - 100 \\ =\; & (3\, w)^{2} - (10)^{2} \\ = \; & (3\, w - 10)\, (3\, w + 10)\end{aligned}.

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