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Readme [11.4K]
3 years ago
8

Which linear inequality is represented by the graph?

Mathematics
1 answer:
Dvinal [7]3 years ago
5 0
The correct answer is C: y > 2/3x + 3

(1,4) ⇒ within the shaded region

4 > 2/3(0) + 3
4 > 0 + 3
4 > 3
True

(0,0) ⇒ within the unshaded region

0 > 2/3(0) + 3
0 > 0 + 3
0 > 3
False

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Can you please help me with this question
Degger [83]

Answer:

  B

Step-by-step explanation:

The table that represents a function will have <em>no x-values repeated</em>.

  A. 4 is repeated -- not a function

  B. all x-values are unique -- this is a function

  C. 2 is repeated -- not a function

  D. 3 is repeated -- not a function

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2 years ago
You want to order some T-shirts that cost $14 each. Shipping is $7 per order. If you buy 11 T-shirts, what will the order cost?
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8 0
3 years ago
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FIND om if LO bisects
disa [49]
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7 0
3 years ago
A persons resting heart rate is typically between 60 and 100 beats per minute. Noah looks at his watch, and counts 8 heartbeats
gulaghasi [49]

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4 0
3 years ago
According to a study done by Wakefield Research, the proportion of Americans who can order a meal in a foreign language is 0.47.
UNO [17]

Answer:

Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.

Step-by-step explanation:

We are given that according to a study done by Wake field Research, the proportion of Americans who can order a meal in a foreign language is 0.47.

Suppose a random sample of 200 Americans is asked to disclose whether they can order a meal in a foreign language.

<em>Let </em>\hat p<em> = sample proportion of Americans who can order a meal in a foreign language</em>

The z-score probability distribution for sample proportion is given by;

          Z = \frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion

p = population proportion of Americans who can order a meal in a foreign language = 0.47

n = sample of Americans = 200

Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is given by = P( \hat p > 0.50)

  P( \hat p > 0.06) = P( \frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } > \frac{0.5-0.47}{\sqrt{\frac{0.5(1-0.5)}{200} } } ) = P(Z > 0.85) = 1 - P(Z \leq 0.85)

                                                               = 1 - 0.80234 = <u>0.19766</u>

<em>Now, in the z table the P(Z  </em>\leq <em>x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.85 in the z table which has an area of 0.80234.</em>

Therefore, probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.

4 0
3 years ago
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