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3 years ago

Which linear inequality is represented by the graph?

Mathematics

1 answer:

Dvinal [7]3 years ago

5 0

The correct answer is C: y > 2/3x + 3

(1,4) ⇒ within the shaded region

4 > 2/3(0) + 3
4 > 0 + 3
4 > 3
True

(0,0) ⇒ within the unshaded region

0 > 2/3(0) + 3
0 > 0 + 3
0 > 3
False

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Write the equation of the line with slope -5 and y-intercept 300.

Leokris [45]

The slope-intercept form is y=mx+b

m=slope=-5

y-int/b = 300

so, y = -5x+300 is the equation of the line

8 0

2 years ago

5. Mrs.Weed's puppy weighed o.236 kg when it was born. At the next check-up it weighed 0.37 kg. How much weight had it gained?

musickatia [10]

Answer:

5.) 0.134 kg.

6.) 6.15 km.

7.) 5.9 kg.

Step-by-step explanation:

5.) 0.37 - 0.236 = 0.134

6.) 9.71 - 3.56 = 6.15

7.) 1.7 + 4.2 = 5.9

5 0

3 years ago

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erastovalidia [21]

Answer:7.5

Step-by-step explanation:add all sides and then divide by 4

3 0

3 years ago

Read 2 more answers

Find the missing length indicated

Kisachek [45]

Answer:

Step-by-step explanation:

tanθ = 48/64 = x/48

x = 48²/64 = 36

4 0

3 years ago

Find the volume V obtained by rotating the region bounded by the curves about the given axis.

BartSMP [9]

Using the disk method, the volume is given by the integral

$\displaystyle \pi \int_{\pi/2}^\pi (9\sin(x))^2\,\mathrm dx = 81\pi \int_{\pi/2}^\pi \sin^2(x)\,\mathrm dx$

That is, each disk has a radius of y = 9 sin(x) and hence area = π (9 sin(x))². Add up infinitely many such disks by integrating. Then the volume is

$\displaystyle 81\pi \int_{\pi/2}^\pi \sin^2(x)\,\mathrm dx = \frac{81\pi}2 \int_{\pi/2}^\pi (1-\cos(2x))\,\mathrm dx \\\\ =\frac{81\pi}2 \left(x-\frac{\sin(2x)}2\right)\bigg|_{\pi/2}^\pi \\\\ = \frac{81\pi}2 \left( \left(\pi-\frac{\sin(2\pi)}2\right) - \left(\frac\pi2 - \frac{\sin(\pi)}2\right) \right) \\\\ = \boxed{\frac{81\pi^2}4}$

8 0

3 years ago