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eimsori [14]
2 years ago
8

Which function has x intercept -2 and y intercept 4?

Mathematics
2 answers:
Crazy boy [7]2 years ago
4 0
The answer is C) y - 2x = 4

In standard form y = Mx + b, the functions reads as y = 2x + 4 where b is the x intercept and m is the slope of the function.

posledela2 years ago
4 0

Answer:

C. y - 2x = 4

Step-by-step explanation:

I recommend using an app called desmos from figuring out graphs and things.

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3 years ago
Which of the following are square roots of 265
Studentka2010 [4]

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Step-by-step explanation:

5 0
2 years ago
Braden has $75 to spend for t shirts online. If shipping is $3 , how many " t" t shirts can he buy if theshirts cost $ 8?
inysia [295]

Answer:

9 tshirts

Step-by-step explanation:

Money he had for t shirts= $75

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Money left for t shirts= $75-$3=$72

Cost of 1 t shirt= $8

We can find the answer with two ways:

1st way: tshirts of $8=1

tshirts of $72=72/8

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2nd way: Cost ($) 8 72

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by cross multiply

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7 0
2 years ago
PLEASE HELP ME WITH THIS QUESTION!!! WHATS THE ANSWER?? I WILL GIVE YOU BRAINLIEST AND A THANKS!
Scrat [10]

Answer:

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Step-by-step explanation:

π r^2

=3.14×(8/2)^2

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3 0
2 years ago
Read 2 more answers
Can anyone figure this out?
Verizon [17]

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10})\qquad A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ NA=\sqrt{(6+3)^2+(3-10)^2}\implies NA=\sqrt{130} \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1}) \\\\\\ AD=\sqrt{(6-6)^2+(-1-3)^2}\implies AD=4 \\\\[-0.35em] ~\dotfill


\bf D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1})\qquad N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10}) \\\\\\ DN=\sqrt{(-3-6)^2+(10+1)^2}\implies DN=\sqrt{202}


now that we know how long each one is, let's plug those in Heron's Area formula.


\bf \qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{130}\\ b=4\\ c=\sqrt{202}\\[1em] s=\frac{\sqrt{130}+4+\sqrt{202}}{2}\\[1em] s\approx 14.81 \end{cases} \\\\\\ A=\sqrt{14.81(14.81-\sqrt{130})(14.81-4)(14.81-\sqrt{202})} \\\\\\ A=\sqrt{324}\implies A=18

5 0
3 years ago
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