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Sophie [7]
4 years ago
13

A research firm wants to determine whether there’s a difference in married couples between what the husband earns and what the

wife earns. The firm takesa random sample of married couples and measures the annual salary of each husband and wife. What procedure should the firm use to analyze the data for the mean difference in salary within married couples?
a)One-sample t procedure, matched pair
b)Two-sample t procedure
c)One-sample z procedure, matched pair
d)Two-sample z procedure
e)Not enough information to determine which procedure should be used.
Mathematics
1 answer:
vovangra [49]4 years ago
5 0

Answer:

Two sample t procedure

Step-by-step explanation:

The reason for using the two sample t procedure is that it is mention in the statement that the firm takes a random sample of married couples and measure their annual salary and standard deviations are unknown and they are estimated by using the collected sample of data. Also there are two population in the data. Population one is the annual salary of husband and population two is the annual salary of wife and these are compared using two sample t procedure.

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An advertising company designs a campaign to introduce a new product to a metropolitan area of population 3 Million people. Let
Advocard [28]

Answer:

P(t)=3,000,000-3,000,000e^{0.0138t}

Step-by-step explanation:

Since P(t) increases at a rate proportional to the number of people still unaware of the product, we have

P'(t)=K(3,000,000-P(t))

Since no one was aware of the product at the beginning of the campaign and 50% of the people were aware of the product after 50 days of advertising

<em>P(0) = 0 and P(50) = 1,500,000 </em>

We have and ordinary differential equation of first order that we can write

P'(t)+KP(t)= 3,000,000K

The <em>integrating factor </em>is

e^{Kt}

Multiplying both sides of the equation by the integrating factor

e^{Kt}P'(t)+e^{Kt}KP(t)= e^{Kt}3,000,000*K

Hence

(e^{Kt}P(t))'=3,000,000Ke^{Kt}

Integrating both sides

e^{Kt}P(t)=3,000,000K \int e^{Kt}dt +C

e^{Kt}P(t)=3,000,000K(\frac{e^{Kt}}{K})+C

P(t)=3,000,000+Ce^{-Kt}

But P(0) = 0, so C = -3,000,000

and P(50) = 1,500,000

so

e^{-50K}=\frac{1}{2}\Rightarrow K=-\frac{log(0.5)}{50}=0.0138

And the equation that models the number of people (in millions) who become aware of the product by time t is

P(t)=3,000,000-3,000,000e^{0.0138t}

5 0
4 years ago
Adam buys a car for £15060 which depreciates in value at a rate of 1.5 per year. Work out how much Adam's car will be worth in 9
Step2247 [10]

Answer: £13026.90

Step-by-step explanation:

1.5% of £15060 = 225.90

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15060 - 2033.10 = 13026.90

hope this helps ;)

4 0
3 years ago
Read 2 more answers
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400 x .75 = 300
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8 0
3 years ago
Find the quotient of<br> 2884 and 14
Firdavs [7]

Answer:

206

Step-by-step explanation:

Quotient is simply the answer to a division problem. 2884 / 14 = 206

7 0
3 years ago
Please help me it will mean a lot
Vedmedyk [2.9K]

Answer:

A) a=25

B) b=14

Step-by-step explanation:

A) a/5+3=8

First you need to subtract 3 from both sides.

(a/5+3)-3=(8)-3

Then simplify

a/5=5

Multiply both sides by 5

(a/5)*5=(5)*5

Then simplify

a= 25

B )3b/7-1=5

First you need to add 1 to both sides

(3b/7-1)+1=(5)+1

Simplify

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Multiply both sides by 7

(3b/7)*7=(6)*7

Simplify

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Divide both sides by 3

(3b)/3=(42/3)/3

Simplify

b= 14

(Brainliest???) :P

3 0
3 years ago
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