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3 years ago

. The time of a clock as seen in a mirror is 3:15. The correct time is

Mathematics

2 answers:

Oksana_A [137]3 years ago

8 0

Answer:

3:15 cause a mirror cant change time

Step-by-step explanation:

go in ur mirror and look at the time did it somehow get darker or lighter???

kolbaska11 [484]3 years ago

4 0

Answer:

8:45 i think

Step-by-step explanation:

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Evaluate algebraic expressions 6th grade 1.5 + y2 when y=6

den301095 [7]

If y=6 then y2 equals 36 because 6 times 6 is 36 and 36+1.5 is 37.5

7 0

3 years ago

Suppose PR = 54, solve for QR 4x-1 3x-1 P R

Svet_ta [14]

Answer:

$QR = 23$

Step-by-step explanation:

P, A, and R are collinear.

PR = 54

$PQ = 4x - 1$

$QR = 3x - 1$

To solve for the numerical length of PR, let's generate an equation to find the value of x.

According to the segment addition postulate:

$PQ + QR = PR$

$(4x - 1) + (3x - 1) = 54$ (substitution)

Solve for x

$4x - 1 + 3x - 1 = 54$

Combine like terms

$4x + 3x - 1 - 1 = 54$

$7x - 2 = 54$

Add 2 to both sides

$7x - 2 + 2 = 54 + 2$

$7x = 56$

Divide both sides by 7

$\frac{7x}{7} = \frac{56}{7}$

$x = 8$

$QR = 3x - 1$

Plug in the value of x into the equation

$QR = 3(8) - 1 = 24 - 1$

$QR = 23$

5 0

3 years ago

3α – 3 (α + 2) =10 please help

Sloan [31]

Step-by-step explanation:

3a-3(a+2)=10

3a-3a-6=10

+3 +3

6a-6=10

+6 +6

6a=16

3 0

3 years ago

What is the range of the function f(x) = 4x + 9, given the domain D = {-4, -2, 0, 2}? please help

neonofarm [45]

Since this is a linear function, filling in the minimum and maximum of the domain is sufficient.

f(-4) = -16 + 9 = -7
f(2)= 8 + 9 = 17

So the range of the function (given the domain) :
R = {-7, 17}

8 0

3 years ago

*WILL MARK BRANLIEST PLEASE ANSWER* Guys what is the perimeter? -PHOTO INCLUDED-

Black_prince [1.1K]

$\qquad \qquad\huge \underline{\boxed{\sf Answer}}$

Perimeter of a triangle = sum of measures of each side ;

$\qquad \rightarrow \sf p = 9 \: ft + 8y + 14 \: ft$

$\qquad \rightarrow \sf p =23 \: ft + 8y$

3 0

2 years ago

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. The time of a clock as seen in a mirror is 3:15. The correct time is​

. The time of a clock as seen in a mirror is 3:15. The correct time is