Remember that parallel lines have the same slope.
y=3/7x+11 (in slope intercept form already)
-3x+7y=13 (standard form)
Add 3x to both sides, giving you 7y=3x+13, divide by 7 on both sides, giving
y=3/7x+13/7
Since both equations' slopes' are the same, their graphs will be parallel.
The base of the prism is a 3:4:5 right triangle.
One of the legs is its base and the other is its height. (The longest side is the hypotenuse!)
The area of the triangular base is bh/2 = (9)(12) / 2. There are two of these.
There are also three rectangular sides on the prism.
Their dimensions are 9 by 20, 12 by 20, and 15 by 20.
You can do the arithmetic from here.
And the answer is 828cm ^2
The service fees differ by $1. The per-check fees differ by $0.01. A person would have to write 1/.01 = 100 checks for the two accounts to cost the same.
Please check the attached picture
Answer:
23.92
Step-by-step explanation:
We solve for y:
use trig substitution:
The derivative of x is:
when x=2 
when x=3 
The area is defined as 2xarea:
The area is the integral of the equation:
for range 0 to sec-1(3/2)
Substitute x=2secu
We know that sec²-1 = tan²u
![A=20[\int\limits^a_b {sec^3u} \, du - \int\limits^a_b {secu} \, du]](https://tex.z-dn.net/?f=A%3D20%5B%5Cint%5Climits%5Ea_b%20%7Bsec%5E3u%7D%20%5C%2C%20du%20-%20%5Cint%5Climits%5Ea_b%20%7Bsecu%7D%20%5C%2C%20du%5D)
After simplifying
![A=10[secutanu-ln(secu+tanu)]](https://tex.z-dn.net/?f=A%3D10%5Bsecutanu-ln%28secu%2Btanu%29%5D)
For the range
![A=10[(3/2)\sqrt{5} /2-ln(3/2+\sqrt{5}/2)]](https://tex.z-dn.net/?f=A%3D10%5B%283%2F2%29%5Csqrt%7B5%7D%20%2F2-ln%283%2F2%2B%5Csqrt%7B5%7D%2F2%29%5D)
