The guy wire BD exerts on the telephone pole AC a force P directed along BD. Knowing that P must have a 720-N component perpendi
cu- lar to the pole AC, determine (a) the magnitude of the force P, (b) its component along line AC.
1 answer:
Answer:
Explanation:
- From the diagram, tanФ = opp/Adj = 2.4m/7m
- tanФ = 0.3429. Ф = arctan ( 0.3429 )
- Therefore, Ф = 18.92°
Given force perpendicular to AC from the diagram = 720N
- Resolving vertically; PsinФ = 720
a) P = 720/sin18.92° = 2220N = the magnitude of the force P
b) To get component along line AC;
- resolving horizontally, component along AC = PcosФ
- = 2220 x cos 18.92° = 2100N
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