Question

The guy wire BD exerts on the telephone pole AC a force P directed along BD. Knowing that P must have a 720-N component perpendicu- lar to the pole AC, determine (a) the magnitude of the force P, (b) its component along line AC.

Answer 1

Answer:

Explanation:

• From the diagram, tanФ = opp/Adj = 2.4m/7m

• tanФ = 0.3429. Ф = arctan ( 0.3429 )

• Therefore, Ф = 18.92°

Given force perpendicular to AC from the diagram = 720N

• Resolving vertically; PsinФ = 720

a) P = 720/sin18.92° = 2220N = the magnitude of the force P

b) To get component along line AC;

• resolving horizontally, component along AC = PcosФ

• = 2220 x cos 18.92° = 2100N