Step-by-step explanation:
Answer
311=0.272727...............
311
= 3011×(110)
= 22+811×110
= 2211×110+811×110
= 2×110+8011×1100
= 210+77+311×1100
= 210+7711×1100+311×1100 or
311=210+7100+1100×(311) ........(A)
Now using value of 311 from (A) within (A)
311=210+7100+1100×(210+7100+1100×(311))
= 210+7100+21000+710000+110000×(311))
Now, if we keep on repeating this endlessly
311=210+7100+21000+710000
Answer:
Side lengths = 1.68 ft and width = 3.36 ft.
Step-by-step explanation:
Let the side lengths of the window be L and the width = 2r ( r is also the radius of the semi-circle).
So we have
Perimeter = 2L + 2r + πr = 12
Area = 2rL + 0.5πr^2
From the first equation
2L = 12 - 2r - πr
Substitute for 2L in the equation for the area:
A = r(12 - 2r - πr) + 0.5πr^2
A = 12r - 2r^2 - πr^2 + 0.5πr^2
A = 12r - 2r^2 - 0.5πr^2
We need to find r for the maximum area:
Finding the derivative and equating to zero:
A' = 12 - 4r - πr = 0=
4r + πr = 12
r = 12 / ( 4 + π)
r = 1.68 ft.
So the width of the window = 2 * 1.68 = 3.36 ft.
Now 2L = 12 - 2r - πr
= 12 - 2*1.68 - 1.68π
= 3.36
L = 1.68.
Answer:
15.7% just got it right
Step-by-step explanation:
