B . 5635.6% not for sure but I think that’s the answer
Answer:
I don't know what, I would like to know
Divide both sides by 2
|x-3|>4 and |x-3|<-4
ok so |x-3|<-4 is false, since |x|≥0 always
so we have
|x-3|>4
now assume
x-3>4 and
x-3<-4
x-3>
add 3
x>7
x-3<-4
add 3
x<-1
so
-1>x and x>7
so basically it is all numbers from -∞ to +∞ except from -1 to 7
in interval notaion
(-∞,-1)U(7,∞)
S={x|x<-1 or x>7}
Answer 1200
Step-by-step explanation:
