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Natalija [7]
3 years ago
15

A bag of Takis holds 200 chips when full.

Mathematics
2 answers:
kow [346]3 years ago
7 0

Answer

30 seconds

Step-by-step explanation:

In-s [12.5K]3 years ago
5 0

Answer 1200

Step-by-step explanation:

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A gift box is in the shape of a right rectangular prism, as pictured below.What is the volume, In cubic centimeters, of the gift
nevsk [136]
The length is 24 centimeters and the width is 10 centimeters and the height is 13 centimeters
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3 years ago
Find the slope of the line shown on the graph. Please help! :(
Anna [14]

Answer:

It's really easy just remember rise over run.

Step-by-step explanation:

so you rise 3 and run to the right 3

A great tip that helps me determine if it's positive or neagitve is if you go to the left then it's ALWAYS neagtive but if you go to the right then it's ALWAYS postive

7 0
3 years ago
Read 2 more answers
In a certain assembly plant, three machines B1, B2, and B3, make 30%, 20%, and 50%, respectively. It is known from past experien
diamong [38]

Answer:

The probability that a randomly selected non-defective product is produced by machine B1 is 11.38%.

Step-by-step explanation:

Using Bayes' Theorem

P(A|B) = \frac{P(B|A)P(A)}{P(B)} = \frac{P(B|A)P(A)}{P(B|A)P(A) + P(B|a)P(a)}

where

P(B|A) is probability of event B given event A

P(B|a) is probability of event B not given event A  

and P(A), P(B), and P(a) are the probabilities of events A,B, and event A not happening respectively.

For this problem,

Let P(B1) = Probability of machine B1 = 0.3

P(B2) = Probability of machine B2 = 0.2

P(B3) = Probability of machine B3 = 0.5

Let P(D) = Probability of a defective product

P(N) = Probability of a Non-defective product

P(D|B1) be probability of a defective product produced by machine 1 = 0.3 x 0.01 = 0.003

P(D|B2) be probability of a defective product produced by machine 2 = 0.2 x 0.03 = 0.006

P(D|B3) be probability of a defective product produced by machine 3 = 0.5 x 0.02 = 0.010

Likewise,

P(N|B1) be probability of a non-defective product produced by machine 1 = 1 - P(D|B1) = 1 - 0.003 = 0.997

P(N|B2) be probability of a non-defective product produced by machine 2  = 1 - P(D|B2) = 1 - 0.006 = 0.994

P(N|B3) be probability of a non-defective product produced by machine 3 = 1 - P(D|B3) = 1 - 0.010 = 0.990

For the probability of a finished product produced by machine B1 given it's non-defective; represented by P(B1|N)

P(B1|N) =\frac{P(N|B1)P(B1)}{P(N|B1)P(B1) + P(N|B2)P(B2) + (P(N|B3)P(B3)} = \frac{(0.297)(0.3)}{(0.297)(0.3) + (0.994)(0.2) + (0.990)(0.5)} = 0.1138

Hence the probability that a non-defective product is produced by machine B1 is 11.38%.

4 0
3 years ago
Can someone answer this question?? ​
Andrews [41]

Answer:

don't ask for an explanation. your answer is below.

Step-by-step explanation:

\frac{(xy+1)^x^+^y^-^(^x^+^y^)(x-y)^x^+^yy^2^xx^-^x^-^y}{(xy-1)^y^+^x}

8 0
3 years ago
Which is true about the volume or surface area of these prisms?
r-ruslan [8.4K]
<span>A.


The surface area of A is greater than the surface area of B.</span>
6 0
3 years ago
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