Answer:
See explanation below
Step-by-step explanation:
<u>First we will solve the radical equation</u> (which I guess was problem 1),
Let's start by simplifying it:

Now we will solve the equation by squaring both sides of the equation:

So the calculation for x was that x = -10
However, this does not produce a solution to the equation: When we plug this value into the radical equation we get:

This happens because <u>when we first squared both sides of the equation in the first part of the problem we missed one value for x </u>(remember that all roots have 2 answers, a positive one and a negative one) while squares are always positive.
When we squared the root, we missed one value for x and that is why the calculation does not produce a solution to the equation.
Expand the brackets:
5y + 50 = 40
minus 50 on both sides to get 5y alone
5y = -10
divide both sides by 5 to find y
y= -2
∴ 1/4y = -0.5
The inverse is the symmetrical function relatively to the function y=x. So, it basically means, that to find the inverse, you just need:
1. Switch x and y (or f(x)): x = 5H(x) + 2
2. Solve for y again (or for f(x)):
5H(x) = x -2
H(x) = (x-2)/5
This is the inverse.
No they are not equivalent